PHP URL验证

tangguo

PHP URL验证

java

我知道有无数个线程在问这个问题，但是我一直找不到能够帮助我解决这个问题的线程。

我基本上是在尝试解析大约10,000,000个URL的列表，确保它们按照以下条件有效，然后获取根域URL。该列表几乎包含了您可以想象的所有内容，包括类似的东西（以及预期的格式化网址）：

biy.ly/test [VALID] [return - bit.ly]
example.com/apples?test=1&id=4 [VALID] [return - example.com]
host101.wow404.apples.test.com/cert/blah [VALID] [return - test.com]
101.121.44.xxx [**inVALID**] [return false]
localhost/noway [**inVALID**] [return false]
www.awesome.com [VALID] [return - awesome.com]
i am so awesome [**inVALID**] [return false]
http://404.mynewsite.com/visits/page/view/1/ [VALID] [return - mynewsite.com]
www1.151.com/searchresults [VALID] [return - 151.com]

有人对此有任何建议吗？

阅读 587

2020-11-15

共1个答案

小编典典

^(?:https?://)?(?:[a-z0-9-]+\.)*((?:[a-z0-9-]+\.)[a-z]+)

说明

^                # start-of-line
(?:              # begin non-capturing group
  https?         #   "http" or "https"
  ://            #   "://"
)?               # end non-capturing group, make optional
(?:              # start non-capturing group
  [a-z0-9-]+\.   #   a name part (numbers, ASCII letters, dashes) & a dot
)*               # end non-capturing group, match as often as possible
(                # begin group 1 (this will be the domain name)
  (?:            #   start non-capturing group
    [a-z0-9-]+\. #     a name part, same as above
  )              #   end non-capturing group
  [a-z]+         #   the TLD
)                # end group 1

http://rubular.com/r/g6s9bQpNnC

2020-11-15