小编典典

计算3点(x,y)的曲率

java

我有一个二维欧几里德空间。给出了三点。

例如(p2是中间点):

Point2D p1 = new Point2D.Double(177, 289);
Point2D p2 = new Point2D.Double(178, 290);
Point2D p3 = new Point2D.Double(178, 291);

现在,我想计算这三个点的曲率

double curvature = calculateCurvature(p1, p2, p3);

这该怎么做?是否存在现有方法(没有Java外部库)?


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2020-11-23

共1个答案

小编典典

对于Menger
Curvature,该公式在Wikipedia文章中:

curvature = 4*triangleArea/(sideLength1*sideLength2*sideLength3)

您到底尝试了哪个代码?

给定3分,计算这4个值应该并不难。

以下是一些有用的方法:

/**
 * Returns twice the signed area of the triangle a-b-c.
 * @param a first point
 * @param b second point
 * @param c third point
 * @return twice the signed area of the triangle a-b-c
 */
public static double area2(Point2D a, Point2D b, Point2D c) {
    return (b.x-a.x)*(c.y-a.y) - (b.y-a.y)*(c.x-a.x);
}

/**
 * Returns the Euclidean distance between this point and that point.
 * @param that the other point
 * @return the Euclidean distance between this point and that point
 */
public double distanceTo(Point2D that) {
    double dx = this.x - that.x;
    double dy = this.y - that.y;
    return Math.sqrt(dx*dx + dy*dy);
}

没有更多的事情要做。警告:area2根据点的方向(顺时针或逆时针)返回带符号的双精度型。

2020-11-23