我已经编写了REST Web服务方法setToken(@Context HttpServletRequest request, @Context HttpServletResponse response, @PathParam("token") String token)，HeaderFilter并且SampleServlet。以下是Web服务类`@Path（“ /
service”）公共类Service {

/*@Context 
private ServletContext servletContext;

@Context
private HttpServletRequest request;

@Context
private HttpServletResponse response;*/


@Path("/val/{token}")   
@GET
@Produces("application/xml")
public String setToken(@Context HttpServletRequest request, @Context HttpServletResponse response, @PathParam("token") String token) throws ServletException, IOException {
    String value=token;
    if(request==null){
        System.out.println("Request null");
    }
    System.out.println("Token: " + value);
    if(request!=null){
        request.setAttribute("param", value);
        Wrapper requestWrapper = new Wrapper(request);
        requestWrapper.addHeader("Authorization", token);
        request.getRequestDispatcher("/secure").include(requestWrapper, response);
    }
    return "<token>"+ "<value>"+value+" token value"+"</value>" + "</token>";
}

}`

在setTokenWeb服务方法中，正在SampleServlet使用调用request.getRequestDispatcher("/secure").include(request, response);，而正在使用的URL是http：// localhost：8080 / xxxx / xxxx / service / val /
zzzz。zzzz是要传递的值。URL模式的HeaderFilter和SampleServlet是/安全。现在，问题HeaderFilter没有被调用，而直接调用了“
SampleServlet”。我做错什么了吗？？？请帮助我解决这个问题。