小编典典

PHP数组组合

php

我有一个由7个数字组成的数组(1,2,3,4,5,6,7),我想制作5个数字对,例如(1,2,3,4,5),(1,2,3
,4,6,),(1,2,3,4,7)。(1,2,3,4,5)等于(4,5,3,1,2)

我想知道PHP中是否有函数或任何可以执行此操作的算法?我不知道从哪里开始。你能帮助我吗 ?

我想将7个给定数字的所有组合(它们从数组中取出)放入5个插槽中,而无视顺序


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2020-05-26

共1个答案

小编典典

如果链接断开,这里是代码。

class Combinations implements Iterator
{
    protected $c = null;
    protected $s = null;
    protected $n = 0;
    protected $k = 0;
    protected $pos = 0;

    function __construct($s, $k) {
        if(is_array($s)) {
            $this->s = array_values($s);
            $this->n = count($this->s);
        } else {
            $this->s = (string) $s;
            $this->n = strlen($this->s);
        }
        $this->k = $k;
        $this->rewind();
    }
    function key() {
        return $this->pos;
    }
    function current() {
        $r = array();
        for($i = 0; $i < $this->k; $i++)
            $r[] = $this->s[$this->c[$i]];
        return is_array($this->s) ? $r : implode('', $r);
    }
    function next() {
        if($this->_next())
            $this->pos++;
        else
            $this->pos = -1;
    }
    function rewind() {
        $this->c = range(0, $this->k);
        $this->pos = 0;
    }
    function valid() {
        return $this->pos >= 0;
    }

    protected function _next() {
        $i = $this->k - 1;
        while ($i >= 0 && $this->c[$i] == $this->n - $this->k + $i)
            $i--;
        if($i < 0)
            return false;
        $this->c[$i]++;
        while($i++ < $this->k - 1)
            $this->c[$i] = $this->c[$i - 1] + 1;
        return true;
    }
}


foreach(new Combinations("1234567", 5) as $substring)
    echo $substring, ' ';

12345 12346 12347 12356 12357 12367 12456 12457 12467 12567 13456 13457 13467
13567 14567 23456 23457 23467 23567 24567 34567

2020-05-26