小编典典

使用jquery ajax为jsp更新数据库

jsp

我希望创建一个简单的脚本来动态存储信息,而无需刷新或重定向到另一个页面。在来到这里之前,我已经高低寻求答案,并且我遵循

但是,我仍然无法获取它来存储数据,因为我不知道哪里出错了。另外,我想问一下success: function(msg)

非常感谢!

更新1:遵循Anoop的解决方案后,它可以正常工作。但是,提交数据时会出现这样的弹出窗口

StaffReg.jsp

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">



<html>

<head>

<title>Staff Registration</title>

</head>

<body>

<%-- HTTP header --%>

<%response.addHeader("Cache-Control","no-cache");

            response.addHeader("Pragma","no-cache");

                response.addHeader("Expires","0");

    %>

<%-- Javascript --%>

<script type="text/javascript" src="jquery-1.11.2.min.js"></script>

<script type="text/javascript">

    $(document).ready(function() {

     $('#Register').click(function(e) {

     e.preventDefault();

     $.ajax({

     url: "StaffRegAuth.jsp",

     type: "post",

     data: {

         username: $('#username').val(),

         password: $('#password').val(),

         userGroup: $('#userGroup').val()

     },

     success: function(msg) {

        alert(msg);

     }

     });

});

});

</script>



<%-- Main body --%>

<h1 align="center"> Account Registration: </h1>

  <div align="center">

    <table style="width = 30%" >

      <tr>

        <td> User Name: </td>

        <td><input type="text" id="username"></td>

      </tr>

      <tr>

        <td> Password: </td>

        <td><input type="password" id="password"></td>

      </tr>

      <tr>

      <tr>

        <td> User Group: </td>

        <td><select name = "userGroup" id="userGroup">

            <option value="1">Administrator

            </optin>

            <option value="2">Clerk

            </optin>

            <option value="3">Operations

            </optin>

            <option value="4">Sales

            </optin>

          </select></td>

      </tr>

      <tr>

    </table>

    <input type="submit" value="Register" id="Register">

  </div>

</body>

</html>

StaffRegAuth.jsp

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">



<html>

<head>

<title></title>

</head>

<body>

<%-- Imports --%>

<%@ page import="java.sql.*"%>

<%@ page import="java.util.*"%>

<%@page import="javax.servlet.*" %>

<%@page import="javax.servlet.http.*" %>

<%-- HTTP header --%>

<%response.addHeader("Cache-Control","no-cache");

            response.addHeader("Pragma","no-cache");

                response.addHeader("Expires","0");



    %>

<%-- Variables that will be written --%>

<% String sUsername = request.getParameter("username");

    String sPassword = request.getParameter("password");

    int sUserGroup = Integer.parseInt(request.getParameter("userGroup"));

    %>

<%-- Creating new staff account - writing --%>

<%

    try{

            Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");

            String conURL= "jdbc:odbc:HOD_DATA";

            Connection con = DriverManager.getConnection(conURL);

            Statement st = con.createStatement();

            int status = st.executeUpdate("insert into Staff(username, password, user_group) values('"+sUsername+"','"+sPassword+"',"+sUserGroup+")");



            if(status>0){

                //out.println("Update sucessful");

            }

            else{

                //out.println("Update unsuccessful");

            }



            st.close();

            con.close();

            }



            catch(Exception e){

            out.println(e);

            }



        %>

</body>

</html>

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2020-06-10

共1个答案

小编典典

  1. 删除提交按钮,并使用带有ID作为注册的普通html按钮。
  2. 修改您的html输入类型,并将name属性替换为id属性。例如:使用id =“ username”代替name =“ username”

调试:使用Firebug检查传递给服务器的值。确保提交了正确的ajax请求。

希望能帮助到你。

2020-06-10