因此,我遇到了多个未知长度的promise链的情况。我希望在处理所有链条后执行一些操作。那有可能吗?这是一个例子:
app.controller('MainCtrl', function($scope, $q, $timeout) { var one = $q.defer(); var two = $q.defer(); var three = $q.defer(); var all = $q.all([one.promise, two.promise, three.promise]); all.then(allSuccess); function success(data) { console.log(data); return data + "Chained"; } function allSuccess(){ console.log("ALL PROMISES RESOLVED") } one.promise.then(success).then(success); two.promise.then(success); three.promise.then(success).then(success).then(success); $timeout(function () { one.resolve("one done"); }, Math.random() * 1000); $timeout(function () { two.resolve("two done"); }, Math.random() * 1000); $timeout(function () { three.resolve("three done"); }, Math.random() * 1000); });
在此示例中,我设置了一个$q.all()承诺1,,2和3,这些承诺会在某个随机时间得到解决。然后,我将诺言添加到第一和第三的结尾。我想all在所有链条都解决后解决。这是运行此代码时的输出:
$q.all()
all
one done one doneChained two done three done ALL PROMISES RESOLVED three doneChained three doneChainedChained
有没有办法等待连锁解决?
当所有链条都解决后,我希望所有人解决。
当然,然后将每个链的承诺传递给all()而不是最初的承诺:
all()
$q.all([one.promise, two.promise, three.promise]).then(function() { console.log("ALL INITIAL PROMISES RESOLVED"); }); var onechain = one.promise.then(success).then(success), twochain = two.promise.then(success), threechain = three.promise.then(success).then(success).then(success); $q.all([onechain, twochain, threechain]).then(function() { console.log("ALL PROMISES RESOLVED"); });