案例要求 :
代码如下 :
package main import "fmt" func modifyUser(users map[string]map[string]string,name string){ //判断users中是否有name if users[name] != nil {//有这个用户 users[name]["pwd"] = "888888" } else { //没有这个用户 users[name] = make(map[string]string, 2) users[name]["pwd"] = "888888" users[name]["nickname"] = "小" + name } } func main() { users := make(map[string]map[string]string,10) users["smith"] = make(map[string]string,2) users["smith"]["pwd"] = "999999" users["smith"]["nickname"] = "小花猫" //modifyUser(users, "tom") modifyUser(users,"zhangsan") modifyUser(users, "mary") modifyUser(users, "smith") fmt.Println(users) }
执行结果如下图所示:
原文链接:https://blog.csdn.net/cui_yonghua/article/details/93892724?ops_request_misc=%257B%2522request%255Fid%2522%253A%2522163479651116780366526677%2522%252C%2522scm%2522%253A%252220140713.130102334.pc%255Fblog.%2522%257D&request_id=163479651116780366526677&biz_id=0&utm_medium=distribute.pc_search_result.none-task-blog-2~blog~first_rank_v2~rank_v29-24-93892724.pc_v2_rank_blog_default&utm_term=go&spm=1018.2226.3001.4450