如何使用Javascript或jQuery过滤JSON数据?
这是我的JSON数据:
[{"name":"Lenovo Thinkpad 41A4298","website":"google"}, {"name":"Lenovo Thinkpad 41A2222","website":"google"}, {"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"}, {"name":"Lenovo Thinkpad 41A424448","website":"google"}, {"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"}, {"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]
JavaScript:
obj1 = JSON.parse(jsondata);
现在我只想要包含网站的名称和网站数据等于 “ yahoo”
这是您应该怎么做的方法:(适用于Google查找)
$([ {"name":"Lenovo Thinkpad 41A4298","website":"google222"}, {"name":"Lenovo Thinkpad 41A2222","website":"google"} ]) .filter(function (i,n){ return n.website==='google'; });
更好的 解决方案:(Salman’s)
$.grep( [{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"}], function( n, i ) { return n.website==='google'; });