这是我的xml，需要将其转换为Java。我用过jaxb

<?xml version="1.0"?>
<lm:order Id="PLG24M240U" JD="" aCount="2" SUCount="1" xmlns:lm="http://www.ae.com/Event/Load">
  <lm:master>
   <lm:ID>3</lm:ID>
    <lm:Number>313</lm:Number>
    <lm:ANumber>323</lm:ANumber>     
  </lm:master>
  <lm:detail>
    <lm:ID>3</lm:ID>
    <lm:Number>3131</lm:Number>
    <lm:ANumber>3232</lm:ANumber>      
  </lm:detail>
 <lm:detail>
    <lm:ID>3</lm:ID>
    <lm:Number>3131</lm:Number>
    <lm:ANumber>3232</lm:ANumber>    
  </lm:detail>
  <lm:detail>
    <lm:ID>3</lm:ID>
    <lm:Number>313</lm:Number>
    <lm:ANumber>323</lm:ANumber>    
  </lm:detail>
</lm:order>

并引发以下异常javax.xml.bind.UnmarshalException：意外元素（uri：“
http://www.ae.com/Event/Load ”，本地：“
Order”）。期望的元素是<{} lm：Order>

这是我的解组代码

jaxbContext = JAXBContext.newInstance(Order.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
Order order = (Order) jaxbUnmarshaller.unmarshal(file);
System.out.println(order );

订购Pojo班

import java.util.ArrayList;
import java.util.List;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "lm:Order")
public class OrderPay {
    @XmlAttribute
    private String Id;
    @XmlAttribute
    private String JD;
    @XmlAttribute
    private String aCount;
    @XmlAttribute
    private String pCount;
    /*@XmlElement
    private Master master;
    @XmlElement
    private List<Detail> details = new ArrayList<Detail>();*/

}

您能否也帮助我阅读，当前正在读取文件，需要读取为XML String。