获取目录中所有文件的列表的最佳方法是什么,按日期排序[创建| 修改],在Windows机器上使用python?
这@Greg Hewgill是答案的更详细的版本。这是最符合问题要求的。它区分了创建日期和修改日期(至少在Windows上如此)。
#!/usr/bin/env python from stat import S_ISREG, ST_CTIME, ST_MODE import os, sys, time # path to the directory (relative or absolute) dirpath = sys.argv[1] if len(sys.argv) == 2 else r'.' # get all entries in the directory w/ stats entries = (os.path.join(dirpath, fn) for fn in os.listdir(dirpath)) entries = ((os.stat(path), path) for path in entries) # leave only regular files, insert creation date entries = ((stat[ST_CTIME], path) for stat, path in entries if S_ISREG(stat[ST_MODE])) #NOTE: on Windows `ST_CTIME` is a creation date # but on Unix it could be something else #NOTE: use `ST_MTIME` to sort by a modification date for cdate, path in sorted(entries): print time.ctime(cdate), os.path.basename(path)
例:
$ python stat_creation_date.py Thu Feb 11 13:31:07 2009 stat_creation_date.py
过去,我是通过Python脚本确定目录中最后更新的文件的方式:
import glob import os search_dir = "/mydir/" # remove anything from the list that is not a file (directories, symlinks) # thanks to J.F. Sebastion for pointing out that the requirement was a list # of files (presumably not including directories) files = list(filter(os.path.isfile, glob.glob(search_dir + "*"))) files.sort(key=lambda x: os.path.getmtime(x))
这应该可以根据文件mtime执行你想要的操作。
编辑:请注意,如果需要,还可以使用os.listdir()代替glob.glob()-我在原始代码中使用glob的原因是我想使用glob仅搜索具有特定集合的文件文件扩展名,glob()更适合。要使用listdir,结果如下所示:
os.listdir()
glob.glob()
glob()
import os search_dir = "/mydir/" os.chdir(search_dir) files = filter(os.path.isfile, os.listdir(search_dir)) files = [os.path.join(search_dir, f) for f in files] # add path to each file files.sort(key=lambda x: os.path.getmtime(x))