使用CriteriaBuilder时发生编译错误

小编典典

使用CriteriaBuilder时发生编译错误

java

我正在尝试将此JPA QL转换为条件构建器。JBoss 6.0。

"SELECT ba FROM BankAccount ba WHERE ba.balance >= :amt ORDER BY ba.ownerName ASC"

我根据一些教程编写了此代码。

public List<BankAccount> findWithBalance(int amount) {
    CriteriaBuilder cb = em.getCriteriaBuilder();
    CriteriaQuery<BankAccount> cq = cb.createQuery(BankAccount.class);
    Root<BankAccount> from = cq.from(BankAccount.class);

    ParameterExpression<Integer> balance = cb.parameter(Integer.class);
    cq.select(from);

    Predicate predicate = cb.gt(from.get("balance"), balance);
    cq.where(predicate);

    cq.orderBy(cb.asc(from.get("ownerName")));

    TypedQuery<BankAccount> query = em.createQuery(cq);

    return query.getResultList();
}

但是，我在一行中遇到了一个编译错误：

Predicate predicate = cb.gt(from.get("balance"), balance);

错误是：

The method gt(Expression<? extends Number>, Expression<? extends Number>) in the type CriteriaBuilder is not applicable for the arguments (Path<Object>, ParameterExpression<Integer>)

阅读 213

2020-11-26

共1个答案

小编典典

好吧，我终于找到了调用gt（）方法的正确方法。这是完整的解决方案。在JBoss 6中经过全面测试。

public List<BankAccount> findWithBalance(int amount) {
    CriteriaBuilder cb = em.getCriteriaBuilder();
    CriteriaQuery<BankAccount> cq = cb.createQuery(BankAccount.class);
    Root<BankAccount> from = cq.from(BankAccount.class);

    ParameterExpression<Integer> balance = cb.parameter(Integer.class);
    cq.select(from);

    //Here is the trick!
    Predicate predicate = cb.gt(from.<Integer> get("balance"), balance);

    cq.where(predicate);
    cq.orderBy(cb.asc(from.get("ownerName")));

    TypedQuery<BankAccount> query = em.createQuery(cq);

    query.setParameter(balance, amount);

    return query.getResultList();
}

2020-11-26