我正在地图上绘制一个圆(在用户当前位置上),并且我希望屏幕进行缩放以使圆在全屏中具有一定的边距。我现在正在做什么:
drawCercleAroundPin(_googleMap, DataManager.RADIUS_SEARCH_CERCLE, _location); moveCamera(_googleMap, (10 / ((DataManager.RADIUS_SEARCH_CERCLE / 900) + 1))+10, 2000, _location, null);
好吧,我尝试了一些愚蠢的演算,因为我找不到合适的解决方案…
有人有主意吗?
如果我理解正确,您是否希望地图适合圆形边界?如果是这样的话
像这样加一个圆
mMap.addCircle(new CircleOptions() .center(new LatLng(location.getLatitude(), location.getLongitude())) .radius(100) .strokeColor(Color.RED) .fillColor(Color.BLUE));
那么您需要您的圆的边界框,请阅读此
LatLngBounds bounds = boundsWithCenterAndLatLngDistance(new LatLng(location.getLatitude(), location.getLongitude()),200,200);
并尝试
private static final double ASSUMED_INIT_LATLNG_DIFF = 1.0; private static final float ACCURACY = 0.01f; public static LatLngBounds boundsWithCenterAndLatLngDistance(LatLng center, float latDistanceInMeters, float lngDistanceInMeters) { latDistanceInMeters /= 2; lngDistanceInMeters /= 2; LatLngBounds.Builder builder = LatLngBounds.builder(); float[] distance = new float[1]; { boolean foundMax = false; double foundMinLngDiff = 0; double assumedLngDiff = ASSUMED_INIT_LATLNG_DIFF; do { Location.distanceBetween(center.latitude, center.longitude, center.latitude, center.longitude + assumedLngDiff, distance); float distanceDiff = distance[0] - lngDistanceInMeters; if (distanceDiff < 0) { if (!foundMax) { foundMinLngDiff = assumedLngDiff; assumedLngDiff *= 2; } else { double tmp = assumedLngDiff; assumedLngDiff += (assumedLngDiff - foundMinLngDiff) / 2; foundMinLngDiff = tmp; } } else { assumedLngDiff -= (assumedLngDiff - foundMinLngDiff) / 2; foundMax = true; } } while (Math.abs(distance[0] - lngDistanceInMeters) > lngDistanceInMeters * ACCURACY); LatLng east = new LatLng(center.latitude, center.longitude + assumedLngDiff); builder.include(east); LatLng west = new LatLng(center.latitude, center.longitude - assumedLngDiff); builder.include(west); } { boolean foundMax = false; double foundMinLatDiff = 0; double assumedLatDiffNorth = ASSUMED_INIT_LATLNG_DIFF; do { Location.distanceBetween(center.latitude, center.longitude, center.latitude + assumedLatDiffNorth, center.longitude, distance); float distanceDiff = distance[0] - latDistanceInMeters; if (distanceDiff < 0) { if (!foundMax) { foundMinLatDiff = assumedLatDiffNorth; assumedLatDiffNorth *= 2; } else { double tmp = assumedLatDiffNorth; assumedLatDiffNorth += (assumedLatDiffNorth - foundMinLatDiff) / 2; foundMinLatDiff = tmp; } } else { assumedLatDiffNorth -= (assumedLatDiffNorth - foundMinLatDiff) / 2; foundMax = true; } } while (Math.abs(distance[0] - latDistanceInMeters) > latDistanceInMeters * ACCURACY); LatLng north = new LatLng(center.latitude + assumedLatDiffNorth, center.longitude); builder.include(north); } { boolean foundMax = false; double foundMinLatDiff = 0; double assumedLatDiffSouth = ASSUMED_INIT_LATLNG_DIFF; do { Location.distanceBetween(center.latitude, center.longitude, center.latitude - assumedLatDiffSouth, center.longitude, distance); float distanceDiff = distance[0] - latDistanceInMeters; if (distanceDiff < 0) { if (!foundMax) { foundMinLatDiff = assumedLatDiffSouth; assumedLatDiffSouth *= 2; } else { double tmp = assumedLatDiffSouth; assumedLatDiffSouth += (assumedLatDiffSouth - foundMinLatDiff) / 2; foundMinLatDiff = tmp; } } else { assumedLatDiffSouth -= (assumedLatDiffSouth - foundMinLatDiff) / 2; foundMax = true; } } while (Math.abs(distance[0] - latDistanceInMeters) > latDistanceInMeters * ACCURACY); LatLng south = new LatLng(center.latitude - assumedLatDiffSouth, center.longitude); builder.include(south); } return builder.build(); }
终于打电话
CameraUpdateFactory#newLatLngBounds(bounds, padding);