我正在创建一个应用程序,它将在呼叫状态之前和之后显示吐司消息。我在手机上生成并安装了应用程序。 几天甚至几个小时后,它运行良好。 但是之后,它停止了,为了运行该应用程序,我需要再次打开该应用程序。如何修改我的应用程序以使其运行良好?谢谢
表现
<uses-permission android:name="android.permission.READ_PHONE_STATE" /> <uses-permission android:name="android.permission.READ_CALL_LOG" /> <uses-permission android:name="android.permission.PROCESS_OUTGOING_CALLS" /> <uses-permission android:name="android.permission.INTERNET" /> <application android:allowBackup="true" android:icon="@mipmap/ic_launcher" android:label="@string/app_name" android:roundIcon="@mipmap/ic_launcher_round" android:supportsRtl="true" android:theme="@style/AppTheme"> <activity android:name=".MainActivity"></activity> <activity android:name=".MainActivity2"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <!-- This part is inside the application --> <receiver android:name=".CallReceiver" android:enabled="true"> <intent-filter android:priority="999"> <action android:name="android.intent.action.PHONE_STATE" /> <action android:name="android.intent.action.BOOT_COMPLETED" /> <action android:name="android.intent.action.NEW_OUTGOING_CALL" /> </intent-filter> </receiver> </application> </manifest>
MainActivity.class
@Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); checkAndRequestPermissions(); } private boolean checkAndRequestPermissions() { int readPhoneState = ContextCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE); int read_call_log = ContextCompat.checkSelfPermission(this, Manifest.permission.READ_CALL_LOG); List listPermissionsNeeded = new ArrayList<>(); if (readPhoneState != PackageManager.PERMISSION_GRANTED) { listPermissionsNeeded.add(Manifest.permission.READ_PHONE_STATE); } if (read_call_log != PackageManager.PERMISSION_GRANTED) { listPermissionsNeeded.add(Manifest.permission.READ_CALL_LOG); } if (read_call_log != PackageManager.PERMISSION_GRANTED) { listPermissionsNeeded.add(Manifest.permission.PROCESS_OUTGOING_CALLS); } if (read_call_log != PackageManager.PERMISSION_GRANTED) { listPermissionsNeeded.add(Manifest.permission.INTERNET); } if (!listPermissionsNeeded.isEmpty()) { ActivityCompat.requestPermissions(this, (String[]) listPermissionsNeeded.toArray(new String[listPermissionsNeeded.size()]), REQUEST_ID_MULTIPLE_PERMISSIONS); return false; } return true; }
CallReciver.class
public class CallReceiver extends BroadcastReceiver{ @Override public void onReceive(Context context, Intent intent) { try { runfirstTime(context,intent); Toast.makeText(context, "1st", Toast.LENGTH_SHORT).show(); } catch (Exception ex) { try { } catch (Exception e) { } } } }
除非创建前台服务,否则新版本的Android不允许您执行您要实现的目标。
Android不想在没有用户明确知识的情况下在后台运行应用程序。
因此,您需要创建一个前台服务,并在通知面板中显示持久性通知。然后,您可以从前景服务中创建一个BroadcastReceiver。
使用以下代码将您的服务作为前台服务启动
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) { context.startForegroundService(intent); } else { context.startService(intent); }
并在服务中onCreate()做这样的事情:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) { startForeground(1, new Notification()); }
下面的链接将使您对前景服务有更多的了解。
https://blog.logimonk.com/post/foreground-service-in- android
https://medium.com/@debuggingisfun/android-o-work-around-background-service- limitation-e697b2192bc3
从服务创建您的BroadcastReceiver。