小编典典

为什么先跳过for循环迭代?

java

我的代码产生了意外的结果。看来我的for循环跳过了第一次迭代,我不明白为什么。

public static void main(String[] args) {

    Scanner get = new Scanner(System.in);
    int number;

    // Ex.1.

    String family_name;
    String[] family_array;

    System.out.println("Enter number of family members: ");
    number = get.nextInt();
    family_array = new String[number];

    for(int i = 0; i < number; i++){
        System.out.println("Enter family member name: ");
        family_name = get.nextLine();
        family_array[i] = family_name;
    }

    for(int i = 0; i < number; i++){
        System.out.println(family_array[i]);
    }

}

返回…(假设输入的数字是姓名)

Enter number of family members: 
5
Enter family member name: 
Enter family member name: 
1
Enter family member name: 
2
Enter family member name: 
3
Enter family member name: 
4

1
2
3
4

为什么第一个get.nextLine()被跳过?


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2020-11-30

共1个答案

小编典典

当前,您对Scanner#nextInt的调用不占用换行符,因此将其传递给您的第一次调用Scanner#nextLine,因此
不会 阻塞。

您将需要添加

get.nextLine();

通话后nextInt,您的第一个通话nextLine将阻止IO

2020-11-30