给定一个字符串“ aabbcdeeeeggi”并且k = 3,代码应该找到最长的子字符串,最多包含k个唯一字符。对于上述输入,它应该是“ deeeeggi”。
这是针对Python中问题的一种出色的O(n)解决方案。我正在用Java实现。但是我没有得到所有输入的期望输出。
public class SubStringWithKUniqueCharacters { public static void main(String[] args){ System.out.println(longestSubStringWithUniqueK("aabbcdeeeeggi", 3)); System.out.println(longestSubStringWithUniqueK("aabbcdeeeeggi", 2)); } public static String longestSubStringWithUniqueK(String input, int k){ int len = input.length(); Set<Character> unique = new HashSet<>(); int i = 0; int j = 0; int count = 0; int maxStartIndex = 0; int maxEndIndex = 0; int maxLen = 0; char[] inputArr = input.toCharArray(); while (i<len){ if (count==k && j -i > maxLen){ maxStartIndex = i; maxEndIndex = j; maxLen = maxEndIndex - maxStartIndex; } if (count<k && j<len){ if (unique.add(inputArr[j])){ count++; } j++; } else { if (unique.remove(inputArr[i])){ count--; } i++; } } return input.substring(maxStartIndex,maxEndIndex); } }
这是输出:
eeeeggi //correct output eeeggi //incorrect output
我无法捕获错误所在。任何帮助将非常感激。谢谢
您的实现无法按预期方式运行,因为原始的python解决方案存在错误。我对您的代码做了一些修改。希望现在还好:
public class SubStringWithKUniqueCharacters { public static void main(String[] args){ System.out.println(longestSubStringWithUniqueK("aabbcdeeeeggi", 3)); System.out.println(longestSubStringWithUniqueK("aabbcdeeeeggi", 2)); } public static String longestSubStringWithUniqueK(String input, int k){ int len = input.length(); Set<Character> unique = new HashSet<>(); int i = 0; int j = 0; int count = 0; int maxStartIndex = 0; int maxEndIndex = 0; int maxLen = 0; char[] inputArr = input.toCharArray(); while (i<len){ if (count==k && j -i > maxLen){ maxStartIndex = i; maxEndIndex = j; maxLen = maxEndIndex - maxStartIndex; } // 1. if we reach the end of the string, we're done. if (j + 1 > len){ break; } // 2. changed to count <= k here else if (count<= k && j<len){ if (unique.add(inputArr[j])){ count++; } j++; } else { if (unique.remove(inputArr[i])){ // 3. remove all consecutive chars of the same value char c = inputArr[i]; // save as temp char while (inputArr[i] == c) { i++; } count--; } } } return input.substring(maxStartIndex,maxEndIndex); } }
现在的输出是:
deeeegg eeeegg