小编典典

仅将文件中的特定文本添加到数组列表,第2部分-Java

java

我希望我能提出一些很好的建议,以解决这个问题:

我有一个带有位置和名称的文本文件-名称详细信息指示此人访问过的位置:

Place: New York
Place: London
Place: Paris
Place: Hongkong

1. Name: John
1. Name detail: London
1. Name detail: Paris
1. Name detail: Hongkong

2. Name: Sarah
2. Name detail: London

3. Name: David
3. Name detail: New York
3. Name detail: Paris

这是我的代码的一部分。

private ArrayList<Place> places = new ArrayList<>();
private ArrayList<Name> names = new ArrayList<>();


public void load(String fileName) throws FileNotFoundException {
    ArrayList<Place> place = places;
    BufferedReader br = new BufferedReader(new FileReader(fileName));
    int nameCounter = 1;
    int nameDetailCounter = 1;
    String text;

    try {
        while ((text = br.readLine()) != null) {     
            if (text.contains("Place:")) {
                text = text.replaceAll("Place:", "");
                places.add(new Place(text));
            } else if (text.contains(nameCounter + ". Name:")) {
                text = text.replaceAll(nameCounter + ". Name:", "");
                names.add(new Name(text, ""));
                nameCounter ++;
            }
                //starting from here!
                else if (text.contains(nameDetailCounter + ". Name detail:")) {
                text = text.replaceAll(nameDetailCounter + ". Name detail:", "");
                for (Name name : names) {
                    Name nameDetails = findName(name.getName());
                    Place placeDetails = findPlace(text);
                    nameDetails.addName(placeDetails);  
                }
                nameDetailCounter ++;
            }
        }
    } catch (Exception e) {
        System.err.println("Error: " + e.getMessage());
    }
}

我的想法是选择所有“ 1”。首先从文本文件添加到数组中,然后继续所有“ 2”。并将其添加到数组中,依此类推。

我已经尝试了许多方法,但是并没有以“ 1”开头添加所有“名称”详细信息。在数组中。感谢您提出的任何新想法或建议,谢谢!


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2020-12-03

共1个答案

小编典典

最好使用正则表达式提取行上的数字,而不要尝试跟踪/猜测它(请参见下文)。

这是对代码的一种经过测试的重新创建,因为您引用了一些您未提供的类…但这有望对您有所帮助:

public static String getMatch(final String pattern, final String content) {
    Pattern r = Pattern.compile(pattern);
    Matcher m = r.matcher(content);

    if (m.find()) {
        return m.group(1);
    } else {
        return "";
    }
}

public static void load(String fileName) throws FileNotFoundException {

    List<String> places = new ArrayList<String>();
    List<String> names = new ArrayList<String>();
    List<String> nameDetails = new ArrayList<String>();

    BufferedReader br = new BufferedReader(new FileReader(fileName));

    String text;
    String lastName = "";

    try {

        while ((text = br.readLine()) != null) {
            // extract num from start of line or empty if none..
            String num = getMatch("^([0-9]+)\\.", text);

            if (text.contains("Place:")) {
                text = text.replaceAll("Place:", "");
                places.add(text);
            } else if (text.contains(num + ". Name:")) {
                text = text.replaceAll(num + ". Name:", "");
                names.add(text);
                lastName = text;
            } else if (text.contains(num + ". Name detail:")) {
                text = text.replaceAll(num + ". Name detail:", "");
                nameDetails.add(lastName + " had " + text);
            }
        }
    } catch (Exception e) {
        System.err.println("Error: " + e.getMessage());
    }

    System.out.println("Places:" + places);
    System.out.println("Names:" + names);
    System.out.println("Name Details:" + nameDetails);
}
2020-12-03