我已经继承了一些Java RMI客户端/服务器代码,尽管它在一台机器上可以正常运行,但我无法使其在我的开发环境中运行。
问题是当我使用以下命令运行服务器时 java.exe -Djava.security.policy=conf\server.policy -SRC;. -Djava.library.path=. org.prog.rmi.RmiServer
java.exe -Djava.security.policy=conf\server.policy -SRC;. -Djava.library.path=. org.prog.rmi.RmiServer
我收到以下错误:
java.rmi.ServerException: RemoteException occurred in server thread; nested exception is: java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is: java.lang.ClassNotFoundException: org.prog.rmi.RmiServer_Stub (no security manager: RMI class loader disabled) at sun.rmi.server.UnicastServerRef.oldDispatch(UnicastServerRef.java:396) at sun.rmi.server.UnicastServerRef.dispatch(UnicastServerRef.java:250) at sun.rmi.transport.Transport$1.run(Transport.java:159) at java.security.AccessController.doPrivileged(Native Method) at sun.rmi.transport.Transport.serviceCall(Transport.java:155) at sun.rmi.transport.tcp.TCPTransport.handleMessages(TCPTransport.java:535) at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run0(TCPTransport.java:790) at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run(TCPTransport.java:649) ...
我的server.policy档案是
server.policy
grant { permission java.security.AllPermission; };
而我的Java代码:
package org.prog.rmi; import java.rmi.Naming; import java.rmi.RemoteException; import java.rmi.RMISecurityManager; import java.rmi.server.UnicastRemoteObject; import java.rmi.registry.*; public class RmiServer extends UnicastRemoteObject implements RmiServerIntf { private BatchApi bapi; private String iniFileLocation; private String layoutOption; private int addressCount = 0; private RefInt apiHandle = new RefInt(); public RmiServer(String iniFileLocation,String layoutOption) throws RemoteException { super(); this.iniFileLocation = iniFileLocation; this.layoutOption = layoutOption; initAPI(); startupAPI(); openAPI(); } public static void main(String args[]) { System.out.println("RMI server started"); // Create and install a security manager if (System.getSecurityManager() == null) { System.setSecurityManager(new RMISecurityManager()); System.out.println("Security manager installed."); } else System.out.println("Security manager already exists."); try //special exception handler for registry creation { LocateRegistry.createRegistry(1099); System.out.println("java RMI registry created."); } catch (RemoteException e) { //do nothing, error means registry already exists System.out.println("java RMI registry already exists."); } try { //Instantiate RmiServer for (String arg: args){ System.out.println(arg); } RmiServer obj = new RmiServer(args[0],args[1]); // Bind this object instance to the name "RmiServer" Naming.rebind("//127.0.0.1/RmiServer", obj); System.out.println("PeerServer bound in registry"); } catch (Exception e) { System.err.println("RMI server exception:"); e.printStackTrace(); } } }
我已经看到了有关的解决方案,java.rmi.server.codebase但也没有设置任何运气
java.rmi.server.codebase
经过进一步调查并遵循RMI教程后,似乎端口1099上的RMI注册服务器出现问题。
当我在另一个端口(例如2005)上注视RMI注册服务器并更改这些代码行时
LocateRegistry.createRegistry(2005);
和
Naming.rebind("//127.0.0.1:2055/RmiServer", obj);
成功运行,没有错误,我的客户端能够连接。
我希望这个答案可以帮助其他人解决这个错误。让我知道是否有人需要更详细的信息。