小编典典

Java RMI ServerException- java.lang.ClassNotFoundException:org.prog.rmi.RmiServer_Stub

java

我已经继承了一些Java RMI客户端/服务器代码,尽管它在一台机器上可以正常运行,但我无法使其在我的开发环境中运行。

问题是当我使用以下命令运行服务器时 java.exe -Djava.security.policy=conf\server.policy -SRC;. -Djava.library.path=. org.prog.rmi.RmiServer

我收到以下错误:

java.rmi.ServerException: RemoteException occurred in server thread; nested exception is: 
java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is: 
java.lang.ClassNotFoundException: org.prog.rmi.RmiServer_Stub (no security manager: RMI class loader disabled)
    at sun.rmi.server.UnicastServerRef.oldDispatch(UnicastServerRef.java:396)
    at sun.rmi.server.UnicastServerRef.dispatch(UnicastServerRef.java:250)
    at sun.rmi.transport.Transport$1.run(Transport.java:159)
    at java.security.AccessController.doPrivileged(Native Method)
    at sun.rmi.transport.Transport.serviceCall(Transport.java:155)
    at sun.rmi.transport.tcp.TCPTransport.handleMessages(TCPTransport.java:535)
    at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run0(TCPTransport.java:790)
    at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run(TCPTransport.java:649)
    ...

我的server.policy档案是

grant {
    permission java.security.AllPermission;
};

而我的Java代码:

        package org.prog.rmi;

        import java.rmi.Naming;
        import java.rmi.RemoteException;
        import java.rmi.RMISecurityManager;
        import java.rmi.server.UnicastRemoteObject;
        import java.rmi.registry.*;

        public class RmiServer extends UnicastRemoteObject 
            implements RmiServerIntf {

        private BatchApi bapi;
        private String iniFileLocation;
        private String layoutOption;
        private int addressCount = 0;
        private RefInt apiHandle = new RefInt();


        public RmiServer(String iniFileLocation,String layoutOption) throws RemoteException 
        {   super();
            this.iniFileLocation = iniFileLocation;
            this.layoutOption = layoutOption;
            initAPI();
            startupAPI();
            openAPI();      
        }

        public static void main(String args[]) 
        {
            System.out.println("RMI server started");

            // Create and install a security manager
            if (System.getSecurityManager() == null) 
            {
                System.setSecurityManager(new RMISecurityManager());
                System.out.println("Security manager installed.");
            }
            else
                System.out.println("Security manager already exists.");

            try  //special exception handler for registry creation
            {
                LocateRegistry.createRegistry(1099); 
                System.out.println("java RMI registry created.");
            }
            catch (RemoteException e)
            {
                //do nothing, error means registry already exists
                System.out.println("java RMI registry already exists.");
            }

            try
            {
                //Instantiate RmiServer
                for (String arg: args){
                    System.out.println(arg);
                }

                RmiServer obj = new RmiServer(args[0],args[1]);

                // Bind this object instance to the name "RmiServer"
                Naming.rebind("//127.0.0.1/RmiServer", obj);
                System.out.println("PeerServer bound in registry");

            } 
            catch (Exception e) 
            {
                System.err.println("RMI server exception:");
                e.printStackTrace();
            }
        }    
}

我已经看到了有关的解决方案,java.rmi.server.codebase但也没有设置任何运气


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2020-12-03

共1个答案

小编典典

经过进一步调查并遵循RMI教程后,似乎端口1099上的RMI注册服务器出现问题。

当我在另一个端口(例如2005)上注视RMI注册服务器并更改这些代码行时

LocateRegistry.createRegistry(2005);

Naming.rebind("//127.0.0.1:2055/RmiServer", obj);

成功运行,没有错误,我的客户端能够连接。

我希望这个答案可以帮助其他人解决这个错误。让我知道是否有人需要更详细的信息。

2020-12-03