我有IP地址和掩码,例如10.1.1.1/32。我想检查是否10.1.1.1在该范围内。是否存在可以执行此操作的库或实用程序,或者我需要自己写点东西?
10.1.1.1/32
10.1.1.1
首先,您需要将IP地址转换为flat int,这将更易于使用:
int
String s = "10.1.1.99"; Inet4Address a = (Inet4Address) InetAddress.getByName(s); byte[] b = a.getAddress(); int i = ((b[0] & 0xFF) << 24) | ((b[1] & 0xFF) << 16) | ((b[2] & 0xFF) << 8) | ((b[3] & 0xFF) << 0);
一旦您的IP地址为ints,就可以执行一些算法来执行检查:
int subnet = 0x0A010100; // 10.1.1.0/24 int bits = 24; int ip = 0x0A010199; // 10.1.1.99 // Create bitmask to clear out irrelevant bits. For 10.1.1.0/24 this is // 0xFFFFFF00 -- the first 24 bits are 1's, the last 8 are 0's. // // -1 == 0xFFFFFFFF // 32 - bits == 8 // -1 << 8 == 0xFFFFFF00 mask = -1 << (32 - bits) if ((subnet & mask) == (ip & mask)) { // IP address is in the subnet. }