有没有办法matplotlib直接使用字典中的数据来绘制条形图？
matplotlib
我的字典看起来像这样：
D = {u'Label1':26, u'Label2': 17, u'Label3':30}
我期待
fig = plt.figure(figsize=(5.5,3),dpi=300) ax = fig.add_subplot(111) bar = ax.bar(D,range(1,len(D)+1,1),0.5)
工作，但事实并非如此。
这是错误：
>>> ax.bar(D,range(1,len(D)+1,1),0.5) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/local/lib/python2.7/site-packages/matplotlib/axes.py", line 4904, in bar self.add_patch(r) File "/usr/local/lib/python2.7/site-packages/matplotlib/axes.py", line 1570, in add_patch self._update_patch_limits(p) File "/usr/local/lib/python2.7/site-packages/matplotlib/axes.py", line 1588, in _update_patch_limits xys = patch.get_patch_transform().transform(vertices) File "/usr/local/lib/python2.7/site-packages/matplotlib/patches.py", line 580, in get_patch_transform self._update_patch_transform() File "/usr/local/lib/python2.7/site-packages/matplotlib/patches.py", line 576, in _update_patch_transform bbox = transforms.Bbox.from_bounds(x, y, width, height) File "/usr/local/lib/python2.7/site-packages/matplotlib/transforms.py", line 786, in from_bounds return Bbox.from_extents(x0, y0, x0 + width, y0 + height) TypeError: coercing to Unicode: need string or buffer, float found
您可以通过首先绘制条形图然后设置适当的刻度来分两行进行：
import matplotlib.pyplot as plt D = {u'Label1':26, u'Label2': 17, u'Label3':30} plt.bar(range(len(D)), list(D.values()), align='center') plt.xticks(range(len(D)), list(D.keys())) # # for python 2.x: # plt.bar(range(len(D)), D.values(), align='center') # python 2.x # plt.xticks(range(len(D)), D.keys()) # in python 2.x plt.show()
请注意，倒数第二行应plt.xticks(range(len(D)), list(D.keys()))在python3中读取，因为它会D.keys()返回一个生成器，而matplotlib无法直接使用该生成器。
plt.xticks(range(len(D)), list(D.keys()))
D.keys()
