给定一个特定的日期（例如2011-07-02），我如何找到该日期之后的下一个星期一（或该日的任何工作日）的日期？
import datetime def next_weekday(d, weekday): days_ahead = weekday - d.weekday() if days_ahead <= 0: # Target day already happened this week days_ahead += 7 return d + datetime.timedelta(days_ahead) d = datetime.date(2011, 7, 2) next_monday = next_weekday(d, 0) # 0 = Monday, 1=Tuesday, 2=Wednesday... print(next_monday)
