我有一个gui应用程序,该应用程序有几个窗口和前进和后退按钮。为此,我使用控制器,并在每次更改窗口时将框架抬高到顶部。这是我的控制器代码和典型框架。
import Tkinter as tk # python from tkFileDialog import askopenfilename, asksaveasfilename from analyzer import Options TITLE_FONT = ("Helvetica", 18, "bold") class TennisProgram(tk.Tk): def __init__(self, *args, **kwargs): tk.Tk.__init__(self, *args, **kwargs) # the container is where we'll stack a bunch of frames # on top of each other, then the one we want visible # will be raised above the others container = tk.Frame(self) #Allow the window to be resized # container.resizable(width=True, height=True) container.pack(side="top", fill="both", expand=True) container.grid_rowconfigure(0, weight=1) container.grid_columnconfigure(0, weight=1) #List of options bundles. One bundle for each video self.options_bundle_list = {} self.frames = {} #Init empty array to hold the list of files #Placed in the container so that all views can access it self.files = [] for F in (UploadPage, AnalysisOptionsPage, FormAnalysisOptions, MatchAnalysisOptions, MatchAnalysisOptionsPage2, OutputPage, ProcessingPage): page_name = F.__name__ frame = F(container, self) self.frames[page_name] = frame # put all of the pages in the same location; # the one on the top of the stacking order # will be the one that is visible. frame.grid(row=0, column=0, sticky="nsew") # Name the window self.title("Tennis Analyzer") self.show_frame("UploadPage") def show_frame(self, page_name): '''Show a frame for the given page name''' frame = self.frames[page_name] frame.tkraise() class UploadPage(tk.Frame): #TODO Add logic to remove a file path from the list def __init__(self, parent, controller): tk.Frame.__init__(self, parent) self.controller = controller self.createView() def createView(self): label = tk.Label(self, text="Upload Videos for Analysis", font=TITLE_FONT) label.pack(side="top", fill="x", pady=10) #Listbox to display the list of files to be processed self.path_list = tk.Listbox(self) #Additional options allow listbox to expand as the window is resized self.path_list.pack(fill=tk.BOTH ,expand=True) for path in self.controller.files: self.path_list.insert(tk.END, path) add_vidoes_button = tk.Button(self, text="Add Videos", command=self.choose_files) continue_button = tk.Button(self, text="Continue", command=lambda: self.controller.show_frame("AnalysisOptionsPage")) add_vidoes_button.pack(side=tk.TOP) continue_button.pack(side=tk.BOTTOM) def choose_files_paths(self): #don't want a full GUI, so keep the root window from appearing #self.controller.withdraw() #Get a file name from the user filename = askopenfilename() #Add it to the list of files to be processed self.controller.files.append(filename) self.path_list.insert(tk.END, filename)
我在init中编写的代码执行一次并创建视图,但是我想知道是否有可能在框架每次抬起时都运行一个函数,类似于Android中的onResume函数。我希望这样做,以防某些基础数据发生更改,例如此上载页面中的数据。例如,如果从填充列表视图的数组中删除了一个项目,我希望能够刷新它。
Tkinter具有低级事件,例如<Visibility>和<Map>,这些事件应在页面更改时触发。不幸的是,这些功能并非在所有平台上都能可靠运行。
<Visibility>
<Map>
最简单,最可靠的解决方案是生成您自己的事件。您可以通过在<<和中指定事件来创建并绑定到自定义事件>>(例如:)<<ShowFrame>>。
<<
>>
<<ShowFrame>>
首先,更改show_frame为在事件显示时将其发送到窗口:
show_frame
def show_frame(self, page_name): ... frame.event_generate("<<ShowFrame>>")
接下来,如果需要将每个页面显示为可见,则可以将其绑定到该事件:
class UploadPage(tk.Frame): def __init__(self, parent, controller): ... self.bind("<<ShowFrame>>", self.on_show_frame) def on_show_frame(self, event): print("I am being shown...")