我知道这$("#divId").html()会给我innerHtml。我还需要它的样式（可以通过类的方式定义），可以是内联style属性，也可以是单独<style>标签中的所有样式/类。

可能吗？

更新
如果HTML类似于HTML <div id="testDiv">cfwcvb</div>并且#testDiv在外部样式表中定义了CSS类，该怎么办？

UPDATE 2
对不起，您没有在此澄清

如果这是我的HTML

<div id="divId">
    <span class="someClass">Some innerText</span>
</div>

样式在单独的样式表或头部样式中定义。

#divId {
    clear: both;
    padding: 3px;
    border: 2px dotted #CCC;
    font-size: 107%;
    line-height: 130%;
    width: 660px;
}
.someClass {
    color: blue;
}

然后，当我尝试获取的内部html $("#divId").html()或调用任何其他自定义函数时，我需要以下内容

<style>
#divId {
    clear: both;
    padding: 3px;
    border: 2px dotted #CCC;
    font-size: 107%;
    line-height: 130%;
    width: 660px;
}
.someClass {
    color: blue;
}
</style>

<div id="divId">
    <span class="someClass">Some innerText</span>
</div>

答案UPDATE 3
我在此页面本身的Chrome调试器工具的命令窗口中运行了以下代码，这就是我所看到的TypeError:Cannot read property 'rules' of undefined

function getElementChildrenAndStyles(selector) {
  var html = $(selector).get(0).outerHTML;

  selector = selector.split(",").map(function(subselector){
    return subselector + "," + subselector + " *";
  }).join(",");
  elts = $(selector);

  var rulesUsed = [];
  // main part: walking through all declared style rules
  // and checking, whether it is applied to some element
  sheets = document.styleSheets;
  for(var c = 0; c < sheets.length; c++) {
    var rules = sheets[i].rules || sheets[i].cssRules;
    for(var r = 0; r < rules.length; r++) {
      var selectorText = rules[r].selectorText;
      var matchedElts = $(selectorText);
      for (var i = 0; i < elts.length; i++) {
        if (matchedElts.index(elts[i]) != -1) {
          rulesUsed.push(CSSrule); break;
        }
      }
    }
  }
  var style = rulesUsed.map(function(cssRule){
    if ($.browser.msie) {
      var cssText = cssRule.style.cssText.toLowerCase();
    } else {
      var cssText = cssRule.cssText;
    }
    // some beautifying of css
    return cssText.replace(/(\{|;)\s+/g, "\$1\n  ").replace(/\A\s+}/, "}");
    //                 set indent for css here ^ 
  }).join("\n");
  return "<style>\n" + style + "\n</style>\n\n" + html;
};
getElementChildrenAndStyles(".post-text:first");