我有一个类似的元组列表：
[(1,a),(2,b), (1, e), (3, b), (2,c), (4,d), (1, b), (0,b), (6, a), (8, e)]
我想将其拆分为列表中每个“ b”的列表
[[(1,a),(2,b)], [(1, e), (3, b)], [(2,c), (4,d), (1, b)], [(0,b)], [(6, a), (8, e)]]
有什么pythonic的方法可以做到这一点吗？
my_list = [(1, "a"),(2, "b"), (1, "e"), (3, "b"), (2, "c"), (1, "b"), (0, "b")] result, temp = [], [] for item in my_list: temp.append(item) if item[1] == 'b': result.append(temp) temp = [] if len(temp) > 0: result.append(temp) print result # [[(1, 'a'), (2, 'b')], [(1, 'e'), (3, 'b')], [(2, 'c'), (1, 'b')], [(0, 'b')]]
