情况:
因此,我在SQLAlchemy中使用关联表具有基本的多对多关系。 例如,一个人可以参加许多聚会,而一个聚会可以有许多人作为客人:
class Person(Base): __tablename__ = 'person' id = Column(Integer, primary_key=True) name = db.Column(db.String(50)) class SexyParty(Base): __tablename__ = 'sexy_party' id = Column(Integer, primary_key=True) guests = relationship('Person', secondary='guest_association', lazy='dynamic', backref='parties') guest_association = Table( 'guest_association', Column('user_id', Integer(), ForeignKey('person.id')), Column('sexyparty.id', Integer(), ForeignKey('sexyparty.id')) )
通常,如果我想添加参加聚会的嘉宾列表,我会执行以下操作:
my_guests = [prince, olivia, brittany, me] my_party.guests = guests db.session.commit()
…其中prince,olivia和brittany都是<Person>实例,而my_party是<SexyParty>实例。
<Person>
<SexyParty>
我的问题 :
我想使用个人ID而不是实例将客人添加到聚会中。例如:
guest_ids = [1, 2, 3, 5] my_party.guests = guest_ids # <-- This fails, because guest_ids # are not <Person> instances
我总是可以从数据库中加载实例,但这将导致不必要的数据库查询,只是为了设置简单的多对多关系。
我将如何.guests使用person_id的列表来设置属性?必须有一种简单的方法来执行此操作,因为关联表最终还是使用ID来表示多对多关系…
.guests
预先感谢,希望问题清楚。
from sqlalchemy import * from sqlalchemy.orm import * from sqlalchemy.ext.declarative import declarative_base Base = declarative_base() class Person(Base): __tablename__ = 'person' id = Column(Integer, primary_key=True) name = Column(String(50)) class SexyParty(Base): __tablename__ = 'sexy_party' id = Column(Integer, primary_key=True) guests = relationship('Person', secondary='guest_association', lazy='dynamic', backref='parties') guest_association = Table( 'guest_association', Base.metadata, Column('user_id', Integer(), ForeignKey('person.id'), primary_key=True), Column('sexyparty_id', Integer(), ForeignKey('sexy_party.id'), primary_key=True) ) e = create_engine("sqlite://", echo=True) Base.metadata.create_all(e) sess = Session(e) p1 = Person(id=1, name='p1') p2 = Person(id=2, name='p2') p3 = Person(id=3, name='p3') p4 = Person(id=4, name='p4') sp1 = SexyParty(id=1) sess.add_all([sp1, p1, p2, p3, p4]) sess.commit() # method one. use insert() sess.execute(guest_association.insert().values([(1, 1), (2, 1)])) # method two. map, optional association proxy from sqlalchemy.ext.associationproxy import association_proxy class GuestAssociation(Base): __table__ = guest_association party = relationship("SexyParty", backref="association_recs") SexyParty.association_ids = association_proxy( "association_recs", "user_id", creator=lambda uid: GuestAssociation(user_id=uid)) sp1.association_ids.extend([3, 4]) sess.commit()