小编典典

如何从图中提取点?

python

我有个问题。

我已经使用Matplotlib绘制了这样的图形:

from matplotlib import pyplot
import numpy
from scipy.interpolate import spline

widths = numpy.array([0, 30, 60, 90, 120, 150, 180])
heights = numpy.array([26, 38.5, 59.5, 82.5, 120.5, 182.5, 319.5])

xnew = numpy.linspace(widths.min(),widths.max(),300)
heights_smooth = spline(widths,heights,xnew)

pyplot.plot(xnew,heights_smooth)
pyplot.show()

现在,我想使用宽度值作为参数来查询高度值。我似乎找不到解决方法。请帮忙!提前致谢!


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2021-01-20

共1个答案

小编典典

plot()返回一个有用的对象:[<matplotlib.lines.Line2D object at 0x38c9910>]
从中,我们可以获得x和y轴的值:

import matplotlib.pyplot as plt, numpy as np
...
line2d = plt.plot(xnew,heights_smooth)
xvalues = line2d[0].get_xdata()
yvalues = line2d[0].get_ydata()

然后,我们可以获得宽度值之一的索引:

idx = np.where(xvalues==xvalues[-2]) # this is 179.3979933110368
# idx is a tuple of array(s) containing index where value was found
# in this case -> (array([298]),)

以及相应的高度:

yvalues[idx]
# -> array([ 315.53469])

要检查,我们可以使用get_xydata()

>>> xy = line2d[0].get_xydata()
>>> xy[-2]
array([ 179.39799331,  315.53469   ])
2021-01-20