请问在PHP中将MySQL查询转换为CSV的最有效方法是什么?
最好避免使用临时文件,因为这会降低可移植性(需要目录路径和设置文件系统权限)。
CSV还应包括一列字段名。
SELECT * INTO OUTFILE “c:/mydata.csv” FIELDS TERMINATED BY ‘,’ OPTIONALLY ENCLOSED BY ‘“’ LINES TERMINATED BY “\n” FROM my_table;
(有关 此文档,请参见: http : //dev.mysql.com/doc/refman/5.0/en/select.html )
要么:
$select = "SELECT * FROM table_name"; $export = mysql_query ( $select ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data";