在这种情况下，“ foo_bar”实际上是“ links_userprofile_favorite_feeds”。

问题是，当我进入manage.py shell时：

manage.py外壳

from django.contrib.auth.models import User
from feeds.models import feed
p = User.objects.get(username='myuser')
p.save()
q = Feed.objects.get(title='myfeed')
q.save()
p.userprofile.favorite_feed.add(q)

我懂了

错误：

ProgrammingError: relation "links_userprofile_favorite_feeds" does not exist
LINE 1: ..."links_userprofile_favorite_feeds"."feed_id" FROM "links_use...

以下是相关文件和回溯：

links.models.py

class UserProfile(models.Model):
    user = models.OneToOneField(User,unique=True)
    bio = models.TextField(null=True)
    thumbnail = models.ImageField(upload_to="uploaded_files/")  
    favorite_feeds = models.ManyToManyField(Feed)

feeds.models.py

class Feed(models.Model):
    title = models.CharField(max_length=25)
    slug = models.SlugField(max_length=25)

    def save(self, *args, **kwargs):
        if not self.slug:
            #Newly created object, so set slug
            self.slug = slugify(self.title)

        super(Feed,self).save(*args,**kwargs)

    def __unicode__(self):
        return self.title

    class Meta:
        ordering = ('title',)

迁移中似乎存在该关系，但是manage.py syncdb, manage.py makemigrations, manage.py migrate，所有关系都不起作用（没有要应用的迁移）。

有人可以帮忙吗？我想建立关系"links_userprofile_favorite_feeds."