那肯定是可能的。我们可以从正常的饼图开始。然后，我们需要将图像放入图中。这是通过plt.imread和通过使用来完成的matplotlib.offsetbox.OffsetImage。我们将需要找到合适的坐标和缩放级别来放置图像，以使其与各自的饼图完全重叠。然后，将饼的楔形路径用作图像的剪切路径，以便仅保留楔形内的部分。将未填充的楔形的zorder设置为较高的数字可确保将边框放置在图像的顶部。这样看起来像是楔子充满了图像。

import matplotlib.pyplot as plt
from matplotlib.patches import PathPatch
from matplotlib.offsetbox import OffsetImage, AnnotationBbox

total = [5,7,4]
labels = ["Raspberries", "Blueberries", "Blackberries"]
plt.title('Berries')
plt.gca().axis("equal")
wedges, texts = plt.pie(total, startangle=90, labels=labels,
                        wedgeprops = { 'linewidth': 2, "edgecolor" :"k","fill":False,  })


def img_to_pie( fn, wedge, xy, zoom=1, ax = None):
    if ax==None: ax=plt.gca()
    im = plt.imread(fn, format='png')
    path = wedge.get_path()
    patch = PathPatch(path, facecolor='none')
    ax.add_patch(patch)
    imagebox = OffsetImage(im, zoom=zoom, clip_path=patch, zorder=-10)
    ab = AnnotationBbox(imagebox, xy, xycoords='data', pad=0, frameon=False)
    ax.add_artist(ab)

positions = [(-1,0.3),(0,-0.5),(0.5,0.5)]
zooms = [0.4,0.4,0.4]

for i in range(3):
    fn = "data/{}.png".format(labels[i].lower())
    img_to_pie(fn, wedges[i], xy=positions[i], zoom=zooms[i] )
    wedges[i].set_zorder(10)

plt.show()