我试图弄清楚如何使Python返回代码的顶部。在SmallBasic中,您可以
start: textwindow.writeline("Poo") goto start
但是我不知道您如何在Python中做到这一点:/有任何想法吗?
我要循环的代码是这样的
#Alan's Toolkit for conversions def start() : print ("Welcome to the converter toolkit made by Alan.") op = input ("Please input what operation you wish to perform. 1 for Fahrenheit to Celsius, 2 for meters to centimetres and 3 for megabytes to gigabytes") if op == "1": f1 = input ("Please enter your fahrenheit temperature: ") f1 = int(f1) a1 = (f1 - 32) / 1.8 a1 = str(a1) print (a1+" celsius") elif op == "2": m1 = input ("Please input your the amount of meters you wish to convert: ") m1 = int(m1) m2 = (m1 * 100) m2 = str(m2) print (m2+" m") if op == "3": mb1 = input ("Please input the amount of megabytes you want to convert") mb1 = int(mb1) mb2 = (mb1 / 1024) mb3 = (mb2 / 1024) mb3 = str(mb3) print (mb3+" GB") else: print ("Sorry, that was an invalid command!") start()
因此,基本上,当用户完成转换时,我希望它循环回到顶部。我仍然不能以此来实践您的循环示例,因为每次我使用def函数进行循环时,都表示未定义“ op”。
像大多数现代编程语言一样,Python不支持“ goto”。而是必须使用控制功能。基本上有两种方法可以做到这一点。
1.循环
您可以如何完全按照SmallBasic示例进行操作的示例如下:
while True : print "Poo"
就这么简单。
2.递归
def the_func() : print "Poo" the_func() the_func()
关于递归的注意事项:仅当您有特定次数要返回到开始时才执行此操作(在这种情况下,添加递归应停止的情况)。像我在上面定义的那样进行无限递归是一个坏主意,因为您最终将耗尽内存!
#Alan's Toolkit for conversions invalid_input = True def start() : print ("Welcome to the converter toolkit made by Alan.") op = input ("Please input what operation you wish to perform. 1 for Fahrenheit to Celsius, 2 for meters to centimetres and 3 for megabytes to gigabytes") if op == "1": #stuff invalid_input = False # Set to False because input was valid elif op == "2": #stuff invalid_input = False # Set to False because input was valid elif op == "3": # you still have this as "if"; I would recommend keeping it as elif #stuff invalid_input = False # Set to False because input was valid else: print ("Sorry, that was an invalid command!") while invalid_input : # this will loop until invalid_input is set to be True start()