小编典典

Java 用于System.out.println()的JUnit测试

java

我需要为设计欠佳的旧应用程序编写JUnit测试,并且正在向标准输出中写入许多错误消息。当getResponse(String request)方法正确运行时,它将返回XML响应:

@BeforeClass
public static void setUpClass() throws Exception {
    Properties queries = loadPropertiesFile("requests.properties");
    Properties responses = loadPropertiesFile("responses.properties");
    instance = new ResponseGenerator(queries, responses);
}

@Test
public void testGetResponse() {
    String request = "<some>request</some>";
    String expResult = "<some>response</some>";
    String result = instance.getResponse(request);
    assertEquals(expResult, result);
}

但是,当XML格式错误或无法理解请求时,它将返回null并将某些内容写入标准输出。

有什么方法可以在JUnit中声明控制台输出?要捕获类似的情况:

System.out.println("match found: " + strExpr);
System.out.println("xml not well formed: " + e.getMessage());

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2020-02-28

共1个答案

小编典典

使用ByteArrayOutputStreamSystem.setXXX很简单:

private final ByteArrayOutputStream outContent = new ByteArrayOutputStream();
private final ByteArrayOutputStream errContent = new ByteArrayOutputStream();
private final PrintStream originalOut = System.out;
private final PrintStream originalErr = System.err;

@Before
public void setUpStreams() {
    System.setOut(new PrintStream(outContent));
    System.setErr(new PrintStream(errContent));
}

@After
public void restoreStreams() {
    System.setOut(originalOut);
    System.setErr(originalErr);
}

样本测试案例:

@Test
public void out() {
    System.out.print("hello");
    assertEquals("hello", outContent.toString());
}

@Test
public void err() {
    System.err.print("hello again");
    assertEquals("hello again", errContent.toString());
}

我使用此代码测试了命令行选项(断言-version输出版本字符串等)

2020-02-28