XQUERY-如何在“ value（）”函数中使用sql：variable？

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XQUERY-如何在“ value（）”函数中使用sql：variable？

sql

下面的查询试图选择给定节点的子节点。如何使用变量而不是对子节点进行硬编码，以便可以将它们作为参数传递给SProc？

declare @T table(XMLCol xml)
insert into @T values
('<Root xmlns="http://tempuri.org" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Elem1 type="T1">
    <Name type="string" display="First name">John</Name>
    <TimeZone display="Time zone">
      <children>
      <DisplayName type="string" display="Display name">GMT Standard Time</DisplayName>
      <HiddenName type="string" display="Hidden name">GMT</HiddenName>
      </children>
    </TimeZone>
  </Elem1>
</Root>')

declare @Node varchar(50)
set @Node = 'TimeZone'

select N.value('(children/DisplayName)[1]', 'varchar(100)') as Value
from @T as T
  cross apply T.XMLCol.nodes('//*[local-name()=sql:variable("@Node")]') as X(N)

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2021-03-10

共1个答案

小编典典

declare @T table(XMLCol xml)
insert into @T values
('<Root xmlns="http://tempuri.org" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Elem1 type="T1">
    <DisplayName type="string" display="Display name">No this</DisplayName>
    <Name type="string" display="First name">John</Name>
    <TimeZone display="Time zone">
      <children>
        <DisplayName type="string" display="Display name">GMT Standard Time</DisplayName>
        <HiddenName type="string" display="Hidden name">GMT</HiddenName>
      </children>
    </TimeZone>
  </Elem1>
</Root>')

declare @Node1 varchar(50)
set @Node1 = 'TimeZone'

declare @Node2 varchar(50)
set @Node2 = 'DisplayName'

select N2.Value.value('.', 'varchar(100)') as Value 
from @T as T
  cross apply (select T.XMLCol.query('//*[local-name()=sql:variable("@Node1")]')) as N1(Value) 
  cross apply (select N1.Value.query('//*[local-name()=sql:variable("@Node2")]')) as N2(Value)

2021-03-10