我将如何在SELECT查询中反转此路径:
z/y/x
为了
x/y/z
其中/是定界符,并且在一行中可以有许多定界符
ex: select (... z/y/x/w/v/u ...) reversed_path from ...
最简单的方法可能是编写一个存储的pl / sql函数,但是可以单独使用SQL(Oracle)来完成。
这将分解子路径中的路径:
SQL> variable path varchar2(4000); SQL> exec :path := 'a/b/c/def'; PL/SQL procedure successfully completed SQL> SELECT regexp_substr(:path, '[^/]+', 1, ROWNUM) sub_path, ROWNUM rk 2 FROM dual 3 CONNECT BY LEVEL <= length(regexp_replace(:path, '[^/]', '')) + 1; SUB_P RK ----- -- a 1 b 2 c 3 def 4
然后,我们使用来重构反向路径sys_connect_by_path:
sys_connect_by_path
SQL> SELECT MAX(sys_connect_by_path(sub_path, '/')) reversed_path 2 FROM (SELECT regexp_substr(:path, '[^/]+', 1, ROWNUM) sub_path, 3 ROWNUM rk 4 FROM dual 5 CONNECT BY LEVEL <= length(regexp_replace(:path, '[^/]', '')) + 1) 6 CONNECT BY PRIOR rk = rk + 1 7 START WITH rk = length(regexp_replace(:path, '[^/]', '')) + 1; REVERSED_PATH ------------- /def/c/b/a