我在以逗号分隔的列中有以下值。
BHOP23,BHOP23,BHOP24
我想知道值是否在列中重复。
我怎样才能做到这一点?
Oracle安装程序 :
CREATE TABLE your_table ( your_list_column ) AS SELECT 'a,a,b,c,d' FROM DUAL UNION ALL -- duplicates both at head SELECT 'a,b,a,c,d' FROM DUAL UNION ALL -- duplicates at head and middle SELECT 'a,b,c,d,a' FROM DUAL UNION ALL -- duplicates at head and tail SELECT 'a,b,b,c,d' FROM DUAL UNION ALL -- duplicates at middle and next item SELECT 'a,b,c,b,d' FROM DUAL UNION ALL -- duplicates at middle and middle SELECT 'a,b,c,d,b' FROM DUAL UNION ALL -- duplicates at middle and tail SELECT 'a,b,c,d,d' FROM DUAL UNION ALL -- duplicates both at tail SELECT 'a,b,a,c,b' FROM DUAL UNION ALL -- two pairs of duplicates SELECT 'a,b,c,d,e' FROM DUAL; -- no duplicates
要获取具有重复值的列表,可以在正则表达式中使用向后引用:
SELECT * FROM your_table WHERE REGEXP_LIKE( ',' || your_list_column || ',', ',([^,]+),(.+,)?\1,' )
输出 :
YOUR_LIST_COLUMN ---------------- a,a,b,c,d a,b,a,c,d a,b,c,d,a a,b,b,c,d a,b,c,b,d a,b,c,d,b a,b,c,d,d a,b,a,c,b
要获取第一个重复值,您可以提取上述正则表达式的第一个子组:
SELECT your_list_column, REGEXP_SUBSTR( ',' || your_list_column || ',', ',([^,]+),(.+,)?\1,', 1, 1, NULL, 1 ) AS duplicate_value FROM your_table WHERE REGEXP_LIKE( ',' || your_list_column || ',', ',([^,]+),(.+,)?\1,' )
YOUR_LIST_COLUMN DUPLICATE VALUE ---------------- --------------- a,a,b,c,d a a,b,a,c,d a a,b,c,d,a a a,b,b,c,d b a,b,c,b,d b a,b,c,d,b b a,b,c,d,d d a,b,a,c,b a
然后,要获取唯一值,请使用split_string()此处定义的函数(但使用用户定义的类型而不是预定义的类型VARRAY):
split_string()
VARRAY
CREATE OR REPLACE TYPE stringlist IS TABLE OF VARCHAR2(4000); / CREATE OR REPLACE FUNCTION split_String( i_str IN VARCHAR2, i_delim IN VARCHAR2 DEFAULT ',' ) RETURN stringlist DETERMINISTIC AS p_result stringlist := stringlist(); p_start NUMBER(5) := 1; p_end NUMBER(5); c_len CONSTANT NUMBER(5) := LENGTH( i_str ); c_ld CONSTANT NUMBER(5) := LENGTH( i_delim ); BEGIN IF c_len > 0 THEN p_end := INSTR( i_str, i_delim, p_start ); WHILE p_end > 0 LOOP p_result.EXTEND; p_result( p_result.COUNT ) := SUBSTR( i_str, p_start, p_end - p_start ); p_start := p_end + c_ld; p_end := INSTR( i_str, i_delim, p_start ); END LOOP; IF p_start <= c_len + 1 THEN p_result.EXTEND; p_result( p_result.COUNT ) := SUBSTR( i_str, p_start, c_len - p_start + 1 ); END IF; END IF; RETURN p_result; END; /
然后,您可以将其与SET()收集功能结合使用:
SET()
SELECT t.*, ( SELECT LISTAGG( COLUMN_VALUE, ',' ) WITHIN GROUP ( ORDER BY ROWNUM ) FROM TABLE( SET( split_string( t.your_list_column ) ) ) ) AS unique_list FROM your_table t
YOUR_LIST_COLUMN UNIQUE_LIST ---------------- --------------- a,a,b,c,d a,b,c,d a,b,a,c,d a,b,c,d a,b,c,d,a a,b,c,d a,b,b,c,d a,b,c,d a,b,c,b,d a,b,c,d a,b,c,d,b a,b,c,d a,b,c,d,d a,b,c,d a,b,a,c,b a,b,c a,b,c,d,e a,b,c,d,e