SQL选择，按时间顺序缺少月份

小编典典

SQL选择，按时间顺序缺少月份

sql

请注意，以下组的输出中缺少2015-02和2015-03月份SQL。如果一个月没有数据，我想显示月份和0。有人知道该怎么做吗？

SELECT convert(char(7), MeterReadDate, 121),count(*)
FROM [myTable]
where (MeterReadDate > dateadd(d,-356,getdate()))
group by  convert(char(7), MeterReadDate, 121)
order by  convert(char(7), MeterReadDate, 121)

样本数据：

YYYY-MM COUNT
2014-06 23
2014-07 42
2014-08 80
2014-09 92
2014-10 232
2014-11 88
2014-12 8
2015-01 5
2015-04 2
2015-05 1

仍然无法清除丢失的行，这是我在其中的位置。

DECLARE @StartDate DATETIME = dateadd(m,-12,getdate()), @EndDate DATETIME = getdate(), @DATE DATETIME

DECLARE @TEMP AS TABLE (MeterReadDate datetime)

SET @DATE = @StartDate

WHILE @DATE <= @EndDate
BEGIN
     INSERT INTO @TEMP VALUES ( @DATE)
    SET @DATE = DATEADD(MONTH,1,@DATE)
END



SELECT convert(char(7), t.MeterReadDate, 121),count(*)

  FROM @TEMP m left join
     [myTable] t
     on convert(char(7), t.MeterReadDate, 121) = convert(char(7), m.MeterReadDate, 121)

  where (t.MeterReadDate > dateadd(m,-12,getdate()))
  group by  convert(char(7), t.MeterReadDate, 121)
  order by  convert(char(7), t.MeterReadDate, 121)

阅读 343

2021-03-10

共1个答案

小编典典

如果您不希望超出结果的日期min和max日期，则可以执行以下操作：

WITH    cte
          AS ( SELECT convert(char(7), MeterReadDate, 121) AS [Date], COUNT(*) AS [Count]
               FROM [myTable]
               WHERE (MeterReadDate > dateadd(d,-356,getdate()))
               GROUP by  convert(char(7), MeterReadDate, 121)
             ),
        minmax
          AS ( SELECT   CAST(MIN([Date] + '-01') AS DATE) AS mind ,
                        CAST(MAX([Date] + '-01') AS DATE) maxd
               FROM     cte
             ),
        calendar
          AS ( SELECT   mind ,
                        CONVERT(CHAR(7), mind, 121) AS cmind
               FROM     minmax
               UNION ALL
               SELECT   DATEADD(mm, 1, calendar.mind) ,
                        CONVERT(CHAR(7), DATEADD(mm, 1, calendar.mind), 121)
               FROM     calendar
                        CROSS JOIN minmax
               WHERE    calendar.mind < minmax.maxd
             )
    SELECT  c.cmind AS [Date],
            ISNULL(cte.[Count], 0) AS [Count]
    FROM    calendar c
            LEFT JOIN cte ON c.cmind = cte.[Date]
    OPTION  ( MAXRECURSION 0 )

2021-03-10