小编典典

为什么我的左联接不返回空值?

sql

在sql server 2008中,我有以下查询:

select      
    c.title as categorytitle,
    s.title as subcategorytitle,
    i.title as itemtitle
from categories c
join subcategories s on c.categoryid = s.categoryid
left join itemcategories ic on s.subcategoryid = ic.subcategoryid 
left join items i on ic.itemid = i.itemid and i.siteid = 132
where (ic.isactive = 1 or ic.isactive is null)
order by c.title, s.title

我正在尝试获取其子类别中的项目,但是如果该类别或子类别中没有项目,我仍然想返回一条记录。没有项目的子类别永远不会返回。我究竟做错了什么?

谢谢

编辑

修改后的查询带有第二个左连接和where子句,但仍不返回null。:/

编辑2

将siteid移至项目左联接。当我这样做时,我会得到比预期更多的记录。有些项目的网站ID为空,我只想在它们具有特定ID时将其包括在内。

编辑3

表结构:

Categories Table 
-------
CategoryID
Title

SubCategories Table
-------
SubCategoryID
CategoryID
Title

ItemCategories Table
-------
ItemCategoryID
ItemID
SubCategoryID
IsActive

Items Table 
--------
ItemID
Title
SiteID

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2021-03-17

共1个答案

小编典典

join items i…更改为LEFT join items i…,您的查询应会按预期工作。

编辑
除非除非考虑到空值,否则您不能在where子句中过滤LEFT JOIN表,因为左连接允许这些列具有值,或者当没有行匹配时为空:

and i.siteid = 132 将丢弃所有i.siteid不存在的NULL的行。将其移动到ON:

left join items i on ic.itemid = i.itemid and i.siteid = 132

或使WHERE处理NULL:

WHERE ... AND (i.siteid = 132 OR i.siteid IS NULL)

编辑 基于OP的编辑3

SET NOCOUNT ON
DECLARE @Categories table (CategoryID int,Title varchar(30))
INSERT @Categories VALUES (1,'Cat AAA')
INSERT @Categories VALUES (2,'Cat BBB')
INSERT @Categories VALUES (3,'Cat CCC')

DECLARE @SubCategories table (SubCategoryID int,CategoryID int,Title varchar(30))
INSERT @SubCategories VALUES (1,1,'SubCat AAA A')
INSERT @SubCategories VALUES (2,1,'SubCat AAA B')
INSERT @SubCategories VALUES (3,1,'SubCat AAA C')
INSERT @SubCategories VALUES (4,2,'SubCat BBB A')

DECLARE @ItemCategories table (ItemCategoryID int, ItemID int, SubCategoryID int, IsActive char(1))
INSERT @ItemCategories VALUES (1,1,2,'Y')
INSERT @ItemCategories VALUES (2,2,2,'Y')
INSERT @ItemCategories VALUES (3,3,2,'Y')
INSERT @ItemCategories VALUES (4,4,2,'Y')
INSERT @ItemCategories VALUES (5,7,2,'Y')

DECLARE @Items table (ItemID int, Title varchar(30), SiteID int)
INSERT @Items VALUES (1,'Item A',111)
INSERT @Items VALUES (2,'Item B',111)
INSERT @Items VALUES (3,'Item C',132)
INSERT @Items VALUES (4,'Item D',111)
INSERT @Items VALUES (5,'Item E',111)
INSERT @Items VALUES (6,'Item F',132)
INSERT @Items VALUES (7,'Item G',132)
SET NOCOUNT OFF

我不确定100%的操作是什么,这将返回所有可以siteid=132在问题中给出的信息加入的信息

SELECT
    c.title as categorytitle
        ,s.title as subcategorytitle
        ,i.title as itemtitle
        --,i.itemID, ic.SubCategoryID, s.CategoryID
    FROM @Items                          i
        LEFT OUTER JOIN @ItemCategories ic ON i.ItemID=ic.ItemID
        LEFT OUTER JOIN @SubCategories   s ON ic.SubCategoryID=s.SubCategoryID
        LEFT OUTER JOIN @Categories      c ON s.CategoryID=c.CategoryID
    WHERE i.siteid = 132

输出:

categorytitle                  subcategorytitle               itemtitle
------------------------------ ------------------------------ ------------------------------
Cat AAA                        SubCat AAA B                   Item C
NULL                           NULL                           Item F
Cat AAA                        SubCat AAA B                   Item G

(3 row(s) affected)

即使没有与之匹配的内容,也会列出所有类别 siteid=132

;WITH AllItems AS
(
SELECT
    s.CategoryID, ic.SubCategoryID, ItemCategoryID, i.ItemID
        ,c.title AS categorytitle, s.title as subcategorytitle, i.title as itemtitle
    FROM @Items                          i
        LEFT OUTER JOIN @ItemCategories ic ON i.ItemID=ic.ItemID
        LEFT OUTER JOIN @SubCategories   s ON ic.SubCategoryID=s.SubCategoryID
        LEFT OUTER JOIN @Categories      c ON s.CategoryID=c.CategoryID
    WHERE i.siteid = 132
)
SELECT
    categorytitle, subcategorytitle,itemtitle
    FROM AllItems
UNION
SELECT
    c.Title, s.Title, null
    FROM @Categories                     c
        LEFT OUTER JOIN @SubCategories   s ON c.CategoryID=s.CategoryID
        LEFT OUTER JOIN @ItemCategories ic ON s.SubCategoryID=ic.SubCategoryID
        LEFT OUTER JOIN AllItems         i ON c.CategoryID=i.CategoryID AND  s.SubCategoryID=i.SubCategoryID
    WHERE i.ItemID IS NULL
ORDER BY categorytitle,subcategorytitle

输出:

categorytitle                  subcategorytitle               itemtitle
------------------------------ ------------------------------ ------------------------------
NULL                           NULL                           Item F
Cat AAA                        SubCat AAA A                   NULL
Cat AAA                        SubCat AAA B                   Item C
Cat AAA                        SubCat AAA B                   Item G
Cat AAA                        SubCat AAA C                   NULL
Cat BBB                        SubCat BBB A                   NULL
Cat CCC                        NULL                           NULL

(7 row(s) affected)
2021-03-17