小编典典

使用别名的ORDER BY中的Postgres CASE

sql

我有以下查询在Postgres 9.1中非常有效:

SELECT users.id, GREATEST(
 COALESCE(MAX(messages.created_at), '2012-07-25 16:05:41.870117'),
 COALESCE(MAX(phone_calls.created_at), '2012-07-25 16:05:41.870117')
) AS latest_interaction
FROM users LEFT JOIN messages ON users.id = messages.user_id
LEFT JOIN phone_calls ON users.id = phone_calls.user_id
GROUP BY users.id
ORDER BY latest_interaction DESC
LIMIT 5;

但是我想做的是这样的:

SELECT users.id, GREATEST(
 COALESCE(MAX(messages.created_at), '2012-07-25 16:05:41.870117'),
 COALESCE(MAX(phone_calls.created_at), '2012-07-25 16:05:41.870117')
) AS latest_interaction
FROM users LEFT JOIN messages ON users.id = messages.user_id
LEFT JOIN phone_calls ON users.id = phone_calls.user_id
GROUP BY users.id
ORDER BY
  CASE WHEN(
    latest_interaction > '2012-09-05 16:05:41.870117')
  THEN 0
  WHEN(latest_interaction > '2012-09-04 16:05:41.870117')
  THEN 2
  WHEN(latest_interaction > '2012-09-04 16:05:41.870117')
  THEN 3
  ELSE 4
  END
LIMIT 5;

而且我收到以下错误:错误:列“ latest_interaction”不存在

似乎我不能在CASE语句的order by子句中使用别名作为聚合的last_interaction的别名。

有什么解决方法吗?


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2021-03-17

共1个答案

小编典典

尝试将其包装为子查询:

SELECT * 
FROM 
(
    SELECT users.id, 
        GREATEST(
             COALESCE(MAX(messages.created_at), '2012-07-25 16:05:41.870117'),
             COALESCE(MAX(phone_calls.created_at), '2012-07-25 16:05:41.870117')
        ) AS latest_interaction
        FROM users LEFT JOIN messages ON users.id = messages.user_id
        LEFT JOIN phone_calls ON users.id = phone_calls.user_id
        GROUP BY users.id
) Sub
ORDER BY
  CASE WHEN(
    latest_interaction > '2012-09-05 16:05:41.870117')
  THEN 0
  WHEN(latest_interaction > '2012-09-04 16:05:41.870117')
  THEN 2
  WHEN(latest_interaction > '2012-09-04 16:05:41.870117')
  THEN 3
  ELSE 4
  END
LIMIT 5;
2021-03-17