我有一张金属表
MetalID integer MetalName text MetalCode text
项目表
ItemID integer ItemName text ... Metal1 int Ref.-> metals.metalID Metal2 int Ref.-> metals.metalID Metal3 int Ref.-> metals.metalID
我正在尝试选择三个MetalCode
SELECT m.MetalCode as 'Metal1', m.MetalCode as 'Metal2',m.MetalCode as 'Metal3' FROM Item as k INNER JOIN Metals AS m ON m.metalID=k.metal1 INNER JOIN Metals AS m ON m.metalID=k.metal2 INNER JOIN Metals AS m ON m.metalID=k.metal3 WHERE k.ItemID=?
看来我做错了。请帮忙。
您应该为表指定不同的别名。您正在呼叫所有这些人。
SELECT m1.MetalCode as 'Metal1', m2.MetalCode as 'Metal2',m3.MetalCode as 'Metal3' FROM Item as k INNER JOIN Metals AS m1 ON m1.metalID=k.metal1 INNER JOIN Metals AS m2 ON m2.metalID=k.metal2 INNER JOIN Metals AS m3 ON m3.metalID=k.metal3 WHERE k.ItemID=?