小编典典

SQLite查询中的子查询不起作用

sql

我正在使用嵌套集模型在iPhone上的本地SQLite数据库中存储较大的数据层次结构。我从他们的网站上阅读了MySQL技术文章,了解如何执行此操作,但是他们建议的查询(以及我需要的查询)之一似乎不适用于SQLite,并且我不确定如何解决它。

SELECT node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM line_items AS node,
    line_items AS parent,
    line_items AS sub_parent,
    (SELECT node.name, (COUNT(parent.name) - 1) AS depth
        FROM line_items AS node,
        line_items AS parent
        WHERE node.lft BETWEEN parent.lft AND parent.rgt
        AND node.name = 'Power Up'
        GROUP BY node.name
        ORDER BY node.lft
    ) AS sub_tree
WHERE node.lft BETWEEN parent.lft AND parent.rgt
    AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
    AND sub_parent.name = sub_tree.name
GROUP BY node.name
HAVING depth <= 1
ORDER BY node.lft;

SQLite报告sub_tree.name不是列,我认为这是因为其子查询实现不完整。有人对如何解决此限制有任何想法吗?

查询的目的是获取给定父节点的所有直接子代。


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2021-03-23

共1个答案

小编典典

尝试在子查询中使用“ node.name AS名称”,即

SELECT node.name, (COUNT(parent.name) - (sub_tree.depth + 1)) AS depth
FROM line_items AS node,
    line_items AS parent,
    line_items AS sub_parent,
    (SELECT node.name AS name, (COUNT(parent.name) - 1) AS depth
        FROM line_items AS node,
        line_items AS parent
        WHERE node.lft BETWEEN parent.lft AND parent.rgt
        AND node.name = 'Power Up'
        GROUP BY node.name
        ORDER BY node.lft
    ) AS sub_tree
WHERE node.lft BETWEEN parent.lft AND parent.rgt
    AND node.lft BETWEEN sub_parent.lft AND sub_parent.rgt
    AND sub_parent.name = sub_tree.name
GROUP BY node.name
HAVING depth <= 1
ORDER BY node.lft;

至少似乎摆脱了错误。

2021-03-23