小编典典

sql触发打印消息

sql

我是在数据库中使用触发器的新手,我创建了一些对我来说效果很好的触发器,除了当我尝试创建一个在删除一行后将显示一条消息的触发器时。

我尝试使用此代码:

ALTER TRIGGER "mycustomerTrigger" 
AFTER delete ON customers
FOR EACH ROW
BEGIN ATOMIC
print 'trigger is working'
END

当我创建此触发器时,它不会给出错误消息,但是当我删除一行时,它不会显示我打印的消息。


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2021-03-23

共1个答案

小编典典

这是因为触发器的运行方式,基本上它不在查询执行窗口中。一种方法是登录到事件查看器。

Create trigger TestTrigger on
tablefortrigger
for insert
as
–Declare variable to hold message
Declare @Msg varchar(8000)
–Assign to message “Action/Table Name/Time Date/Fields inserted
set @Msg = ‘Inserted | tablefortrigger | ‘ + convert(varchar(20), getdate()) + ‘ | ‘
+(select convert(varchar(5), track)
+ ‘, ‘ + lastname + ‘, ‘ + firstname
from inserted)
–Raise Error to send to Event Viewer
raiserror( 50005, 10, 1, @Msg)

执行此操作的另一种方法是写入文件,这里当然存在权限问题,但是您可以执行以下操作:

Alter trigger TestTrigger on
tablefortrigger
for insert
as
Declare @Msg varchar(1000)
–Will hold the command to be executed by xp_cmdshell
Declare @CmdString varchar (2000)
set @Msg = ‘Inserted | tablefortrigger | ‘ + convert(varchar(20), getdate()) + ‘ — ‘
+(select convert(varchar(5), track)
+ ‘, ‘ + lastname + ‘, ‘ + firstname
from inserted)
–Raise Error to send to Event Viewer
raiserror( 50005, 10, 1, @Msg)
set @CmdString = ‘echo ‘ + @Msg + ‘ >> C:logtest.log’
–write to text file
exec master.dbo.xp_cmdshell @CmdString
2021-03-23