小编典典

传递到字典中的模型项的类型为'System.Data.Entity.DynamicProxies.Object

sql

有谁知道为什么我会收到此错误：

The model item passed into the dictionary is of type
system.Data.Entity.DynamicProxies.Object_3E186F803589BF82895B10E08C
2A9AB68EFA619599418D6EB96585D14874CDC0', 
but this dictionary requires a model item of type 
'System.Collections.Generic.IEnumerable`1[MyApplication.Domain.Entities.Object]'.

这是我的代码：

控制器：

        public ViewResult Index()
    {
        if (User.Identity.IsAuthenticated)
        {
            MembershipUser currentUser = Membership.GetUser();
            Guid currentUserId = (Guid)currentUser.ProviderUserKey;
            if (currentUser != null && currentUser.ProviderUserKey != null && currentUser.IsApproved)
            {
                Move result = (from move in db.Moves
                         where move.UserId == currentUserId
                         select move).FirstOrDefault();
                return View(result);
            }
        }
        return View(db.Moves.ToList());
    }

看法：

@model IEnumerable<MovinMyStuff.Domain.Entities.Move>
@{
ViewBag.Title = "Index";
}

@foreach (var item in Model)
{
<div id="move-list-item">
    <ul>
        <li>
            <span class="move-name">
                @Html.DisplayFor(modelItem => item.StartCity) 
                @Html.DisplayFor(modelItem => item.StartState)
                @Html.DisplayFor(modelItem => item.StartZip) -
                @Html.DisplayFor(modelItem => item.EndCity) 
                @Html.DisplayFor(modelItem => item.EndState)
                @Html.DisplayFor(modelItem => item.EndZip)
            </span>
        </li>
        <li>@Html.ActionLink("Details", "Details", new { id = item.MoveId }, new { @class = "button" })</li>
    </ul>
</div>
}

阅读 192

2021-03-23

共1个答案

小编典典

这段代码：

Move result = (from move in db.Moves
         where move.UserId == currentUserId
         select move).FirstOrDefault();
return View(result);

尝试返回单个结果。它抱怨它想要 一系列 结果。因此，您可以使用：

var results = (from move in db.Moves
               where move.UserId == currentUserId
               select move).Take(1).ToList();
return View(results);

或者：

Move result = (from move in db.Moves
         where move.UserId == currentUserId
         select move).FirstOrDefault();
return View(new[] { result });

顺便说一下，我个人将在这里摆脱查询表达式-它使代码变得比所需的更为复杂。例如，您可以将我的第一个选项重写为：

var results = db.Moves.Where(move => move.UserId == currentUserId)
                      .Take(1)
                      .ToList();
return View(results);

甚至：

return View(db.Moves.Where(move => move.UserId == currentUserId)
              .Take(1).ToList());

2021-03-23