我想在PostgreSQL上设置一个返回表的函数。这是该函数的源代码：

   CREATE OR REPLACE FUNCTION feiertag(inDate Date) 
     RETURNS TABLE (eingabeDatum DATE, f_heute INT, f_1 INT, f_2 INT, f_3 INT, f_5 INT) 
    AS $$
            DECLARE
              f_heute integer := 0;
              f_1 integer := 0;
              f_2 integer := 0;
              f_3 integer := 0;
              f_5 integer := 0;
            BEGIN
                    SELECT 1 INTO f_heute FROM feiertage where datum = inDate;
                    SELECT 1 INTO f_1 FROM feiertage where datum = (inDate + interval '1' day);
                    SELECT 1 INTO f_2 FROM feiertage where datum = (inDate + interval '2' day);
                    SELECT 1 INTO f_3 FROM feiertage where datum = (inDate + interval '3' day);
                    SELECT 1 INTO f_5 FROM feiertage where datum = (inDate + interval '5' day);

   RETURN QUERY SELECT inDate as eingabeDatum, coalesce(f_heute, 0) as f_heute, coalesce(f_1,0) as f_1, coalesce(f_2,0) as f_2, coalesce(f_3,0) as f_3, coalesce(f_5,0) as f_5 ;
            END;
    $$ LANGUAGE plpgsql;

调用该函数仅返回一列，并用’，’分隔值：

psql (9.5.12)
Type "help" for help.

tarec=> select feiertag('2017-01-01');
        feiertag        
------------------------
 (2017-01-01,1,0,0,0,0)
(1 row)

我期望有不同的列（在函数的开头为表指定的每个值一个），而不仅仅是所有值的列。有谁知道为什么会这样，我该如何解决？

谢谢蒂莫