SQL查询以查找2个表之间的部分字符串匹配

小编典典

SQL查询以查找2个表之间的部分字符串匹配

sql

我正在尝试在列地址（用户表）中找到在地址（address_effect表）中具有匹配项的任何项目。我正在使用XAMPP在本地系统上对此进行测试（使用MariaDB）

用户表

+------------------+-----------------+------------------+--------------------------+
|        ID        |    firstname    |  lastname        |    address               |
|                  |                 |                  |                          |
+----------------------------------------------------------------------------------+
|     1            |    john         |    doe           |james street, idaho, usa  |                    
|                  |                 |                  |                          |
+----------------------------------------------------------------------------------+
|     2            |    cindy        |   smith          |rollingwood av,lyn, canada|
|                  |                 |                  |                          |
+----------------------------------------------------------------------------------+
|     3            |    rita         |   chatsworth     |arajo ct, fremont, cali   |
|                  |                 |                  |                          |
+------------------+-----------------+---------------------+-----------------------+
|     4            |    randy        |   plies          |smith spring, lima, peru  |                       
|                  |                 |                  |                          |
+----------------------------------------------------------------------------------+
|     5            |    Matt         |   gwalio         |park lane, atlanta, usa   |
|                  |                 |                  |                          |
+------------------+-----------------+------------------+--------------------------+

address_effect表

+---------+----------------+
|idaho    |potato, tater   |
+--------------------------+
|canada   |cold, tundra    |
+--------------------------+
|fremont  | crowded        |
+--------------------------+
|peru     |alpaca          |
+--------------------------+
|atlanta  |peach, cnn      |
+--------------------------+
|usa      |big, hard       |
+--------+-----------------+

我尝试将内部联接与LIKE配合使用以查找匹配的字符串。

如果我使用此查询，则找不到任何项目：

SELECT users.firstname, users.lastname, users.address
FROM users
INNER JOIN db_name.address_effect
ON
(address_effect.Address LIKE '%' + users.address + '%'
OR users.address LIKE '%' || address_effect.Address || '%')

然后，我尝试了以下查询，它列出了用户表中的所有项目，而不是仅列出那些在address_effect中具有匹配项的项目

SELECT DISTINCT users.firstname, users.lastname, users.address
FROM users
INNER JOIN db_name.address_effect
ON
(address_effect.Address LIKE '%' || users.address || '%'
OR users.address LIKE '%' || address_effect.Address || '%')

我在这里想念什么？

谢谢。

阅读 298

2021-04-15

共1个答案

小编典典

据我了解的示例数据，您希望将users地址的一部分与另一张表中的值进行匹配。

您可能想尝试一下find_in_set()。LIKE匹配更为准确，因为它仅匹配单个元素：

SELECT u.firstname, u.lastname, u.address user_address, a.*
FROM users u
INNER JOIN address_effect a 
    ON FIND_IN_SET(a.address, REPLACE(u.address, ', ', ','))

如果address_effect(address)可以在中存储的CSV列表中找到，则与此匹配users(address)。

2021-04-15