我对T-SQL中计算Levenshtein距离的算法感兴趣。
阿诺德Fribble对两个提案sqlteam.com/forums
SET QUOTED_IDENTIFIER ON GO SET ANSI_NULLS ON GO CREATE FUNCTION edit_distance_within(@s nvarchar(4000), @t nvarchar(4000), @d int) RETURNS int AS BEGIN DECLARE @sl int, @tl int, @i int, @j int, @sc nchar, @c int, @c1 int, @cv0 nvarchar(4000), @cv1 nvarchar(4000), @cmin int SELECT @sl = LEN(@s), @tl = LEN(@t), @cv1 = '', @j = 1, @i = 1, @c = 0 WHILE @j <= @tl SELECT @cv1 = @cv1 + NCHAR(@j), @j = @j + 1 WHILE @i <= @sl BEGIN SELECT @sc = SUBSTRING(@s, @i, 1), @c1 = @i, @c = @i, @cv0 = '', @j = 1, @cmin = 4000 WHILE @j <= @tl BEGIN SET @c = @c + 1 SET @c1 = @c1 - CASE WHEN @sc = SUBSTRING(@t, @j, 1) THEN 1 ELSE 0 END IF @c > @c1 SET @c = @c1 SET @c1 = UNICODE(SUBSTRING(@cv1, @j, 1)) + 1 IF @c > @c1 SET @c = @c1 IF @c < @cmin SET @cmin = @c SELECT @cv0 = @cv0 + NCHAR(@c), @j = @j + 1 END IF @cmin > @d BREAK SELECT @cv1 = @cv0, @i = @i + 1 END RETURN CASE WHEN @cmin <= @d AND @c <= @d THEN @c ELSE -1 END END GO