小编典典

如何解决将表达式转换为数据类型int的算术溢出错误?

sql

我有以下查询:

-- CTE to remove outliers, e.g. remove the fastest and slowest results
;WITH MinMaxCTE AS 
(
  SELECT ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101) AS [Date], Version, 
    MIN(JaguarStartupTime) AS MinStartTime, MAX(JaguarStartupTime) AS MaxStartTime
  FROM dbo.MachineConfiguration (NOLOCK)
  WHERE DomainLogin NOT IN (SELECT DomainLogin FROM dbo.SupportGroup)
  GROUP BY ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101), Version
)

SELECT  AVG(mc.JaguarStartupTime) AS AverageTime
    , COUNT(*) AS NumEntries
    , mc.Version
FROM    #Eligible mc (NOLOCK)
JOIN MinMaxCTE cte ON mc.ServerName = cte.ServerName 
  AND CONVERT(VARCHAR(10), mc.UpdatedOn, 101) = cte.[Date] 
  AND mc.Version = cte.Version 
  AND mc.JaguarStartupTime <> cte.MinStartTime 
  AND mc.JaguarStartupTime <> cte.MaxStartTime
GROUP BY mc.Version
ORDER BY Version DESC, AVG(mc.JaguarStartupTime) ASC

Eligible临时表的定义是

create table #Eligible (
    Version nvarchar(50), JaguarStartupTime int, 
    ServerName nvarchar(50), UpdatedOn datetime )

无论我注释掉什么条件或聚合,总是会出现以下错误:Arithmetic overflow error converting expression to data type int

我可以从这里去哪里?如何进一步调试?

编辑:样本数据

Version JaguarStartupTime    ServerName     UpdatedOn
6.4.6.082      16040         NewOrleansLA   2012-08-08 12:34:12.330
6.5.1.012      40390         BatonRougeLA   2012-08-08 18:33:17.440
6.5.1.012      48379         HonoluluHI     2012-08-09 04:42:50.453

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2021-04-19

共1个答案

小编典典

您是否尝试过将jaguarstartup时间强制转换为avg聚合中的bigint,如下所示…

AVG(CAST(mc.JaguarStartupTime AS BIGINT))

这应该解决算术溢出。

要计算平均平均值,服务器需要首先能够对所有int求和,因此要求平均值的数据类型必须能够存储这些值的总和,即使返回的答案在int的范围内

2021-04-19