我在数据库中有一个表,记录如下:
match_id | guess | result 125 | 1 | 0 130 | 5 | 0 233 | 11 | 0 125 | 2 | 0
我的用户为每个匹配项选择一个猜测,我有一个函数可以根据匹配结果计算猜测的结果:如果猜测正确,则结果为(1)如果错误,则结果为(2 ),如果比赛还没有结束,结果将是(默认为0),例如,我有11种猜测的可能性(一次可能有多个正确的猜测):如果我有一场比赛,id = 125,我拥有全部除了8,11之外的其他猜测都是错误的,因此我应该为具有匹配ID的所有匹配更新结果字段,并且其猜测为8或11(我将为此结果字段提供1),而我想为其他字段给出(2)猜对相同的比赛
我将此查询用于所有十一种可能性,如下所示:
UPDATE `tahminler` SET result=1 WHERE match_id='1640482' AND tahmin='8' UPDATE `tahminler` SET result=1 WHERE match_id='1640482' AND tahmin='11' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='1' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='2' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='3' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='4' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='5' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='6' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='7' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='9' UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='10'
我想知道是否可以在一个查询中完成这项工作吗?
使用以下两个查询:
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin IN ('1','2','3','4','5','6','7','9','10')
然后使用:
UPDATE `tahminler` SET result=1 WHERE match_id='1640482' AND tahmin IN ('8','11')