我有2个表格,Chapter表格中有很多行,其中manga_id是Manga表格的ID
Chapter
Manga
漫画桌
ID | NAME | SLUG 1 One Piece one-piece 2 Naruto naruto 3 Gintama gintama
章表
MANGA_ID | NAME | SLUG | CREATED_AT 1 Chap 1 One-Piece-Chap-1 2016/01/01 1 Chap 2 One-Piece-Chap-2 2016/01/02 1 Chap 3 One-Piece-Chap-3 2016/01/03 2 Chap 1 Naruto-Chap-1 2016/01/02 2 Chap 2 Naruto-Chap-2 2016/01/03 2 Chap 3 Naruto-Chap-3 2016/01/04 3 Chap 1 Gintama-Chap-1 2016/01/07 3 Chap 4 Gintama-Chap-4 2016/01/09
我只选择1个漫画,按created_atDESC的顺序排列1章
created_at
我要查找的示例表:
Manga_ID | Manga_NAME | NAME | SLUG | CREATED_AT 3 Gintama Chap 4 Gintama-Chap-4 2016/01/09 2 Naruto Chap 3 Naruto-Chap-3 2016/01/04 1 One Piece Chap 3 One-Piece-Chap-3 2016/01/03
我真的很感谢任何对此主题的回答,并节省我的时间
SELECT mt.id as MANGA_ID, mt.NAME as MANGA_NAME, ct.NAME, ct.SLUG, MAX(ct.CREATED_AT) as CREATED_AT FROM Chapter ct LEFT JOIN Manga mt ON (mt.id = ct.MANGA_ID) GROUP BY ct.MANGA_ID
这应该可以解决问题。