Row_Number（）需要动态枢轴

小编典典

Row_Number（）需要动态枢轴

sql

我正在使用Microsoft SQL Server Management Studio 2008。

我有看起来像这样的数据：

Client ID        Value
-------------------------------
12345            Did Not Meet
12345            Did Not Meet
12345            Partially Met
12346            Partially Met
12346            Partially Met
12346            Partially Met
12347            Partially Met
12347            Partially Met
12347            Did Not Meet
12347            Met

我希望结果显示如下：

Client ID                Value1                Value2                   Value3                      Value4

12345                    Did Not Meet           Did Not Meet            Partially Met                NULL
12346                    Partially Met          Partially Met           Partially Met                NULL
12347                    Partially Met          Partially Met           Did Not Meet                 Met

这些列是未知的，所以我知道我需要一个动态查询。我已经尝试过使用数据透视功能进行动态查询，但只在相同类型的值下进行分组。所以聚合函数对我不利。

这是我尝试过的查询：

Declare @Columns nvarchar(max); 
Declare @DynamicPivotQuery nvarchar(max);

Select @Columns=    
COALESCE(@Columns+',','')+QUOTENAME(Value)  
from (select distinct Document.Value
from Document d 
join Client c on d.clientid=c.id    
    )
 as t1


Set @DynamicPivotQuery= 
 N'Select ClientID, ' + @Columns + '    
 from   
 (select Document.ClientID, 
  DocumentFact.Value,   
   from Document d
   join Client c on d.clientid=c.id 
 ) p    
Pivot (max(Value) for Value in ('+@Columns+'))  
 as pivottable  
 order by ClientID;'

执行（@DynamicPivotQuery）

接下来，我添加了row_number和partition函数，但似乎无法对其进行调试。我得到的错误是：

消息102，级别15，状态1，第29行
‘）’附近的语法不正确。

靠近XML Path函数。

任何帮助，将不胜感激。谢谢。

select @Columns=    
COALESCE(@Columns+',','')+QUOTENAME(Value)  
from (select distinct Document.Value    
, 'name'+ CAST (row_number() over   
(Partition BY clientid order by clientid) as NVARCHAR (10)) as Cols 
from document d
join Clients c on d.clientid=c.id

 t1

 --FOR XML PATH('')),      1, 1, N'');
 FOR XML PATH('')), TYPE).value('.','NVARCHAR(MAX)'),1,2,'')    
  order by ClientID

阅读 171

2021-05-05

共1个答案

小编典典

与一起使用cte，row_number您可以达到以下结果：

您的架构：

create table your_table([Client ID] int ,Value varchar(50));
insert into your_table values
(12345,            'Did Not Meet'),
(12345,            'Did Not Meet'),
(12345,            'Partially Met'),
(12346,            'Partially Met'),
(12346,            'Partially Met'),
(12346,            'Partially Met'),
(12347,            'Partially Met'),
(12347,            'Partially Met'),
(12347,            'Did Not Meet'),
(12347,            'Met');

查询：

with cte as
(
 select [Client ID] ci,value,
        row_number() over(partition by [Client ID] order by value) as rn
 from your_table
)
select distinct ci as [Client ID],
       (select ct.value from cte ct where ct.ci=cte.ci and ct.rn=1) value1,
       (select ct.value from cte ct where ct.ci=cte.ci and ct.rn=2) value2,
       (select ct.value from cte ct where ct.ci=cte.ci and ct.rn=3) value3,
       (select ct.value from cte ct where ct.ci=cte.ci and ct.rn=4) value4
from cte

结果：

Client ID   value1          value2          value3          value4
12345       Did Not Meet    Did Not Meet    Partially Met   (null)
12346       Partially Met   Partially Met   Partially Met   (null)
12347       Did Not Meet    Met Partially   Met Partially    Met

2021-05-05