按分组列值的变化对数据进行分组

admin

按分组列值的变化对数据进行分组

sql

带有以下数据

create table #ph (product int, [date] date, price int)
insert into #ph select 1, '20120101', 1
insert into #ph select 1, '20120102', 1
insert into #ph select 1, '20120103', 1
insert into #ph select 1, '20120104', 1
insert into #ph select 1, '20120105', 2
insert into #ph select 1, '20120106', 2
insert into #ph select 1, '20120107', 2
insert into #ph select 1, '20120108', 2
insert into #ph select 1, '20120109', 1
insert into #ph select 1, '20120110', 1
insert into #ph select 1, '20120111', 1
insert into #ph select 1, '20120112', 1

我想产生以下输出：

product | date_from | date_to  | price
  1     | 20120101  | 20120105 |   1
  1     | 20120105  | 20120109 |   2
  1     | 20120109  | 20120112 |   1

如果我按价格分组并显示最大日期和最小日期，那么我将得到以下不是我想要的内容（请参见重叠的日期）。

product | date_from | date_to  | price
  1     | 20120101  | 20120112 |   1
  1     | 20120105  | 20120108 |   2

因此，基本上我想做的是根据组列产品和价格对数据进行逐步更改。

什么是最干净的方法来做到这一点？

阅读 164

2021-05-10

共1个答案

admin

有一种（或多或少）解决此类问题的已知技术，涉及两个ROW_NUMBER()调用，如下所示：

WITH marked AS (
  SELECT
    *,
    grp = ROW_NUMBER() OVER (PARTITION BY product        ORDER BY date)
        - ROW_NUMBER() OVER (PARTITION BY product, price ORDER BY date)
  FROM #ph
)
SELECT
  product,
  date_from = MIN(date),
  date_to   = MAX(date),
  price
FROM marked
GROUP BY
  product,
  price,
  grp
ORDER BY
  product,
  MIN(date)

输出：

product  date_from   date_to        price 
-------  ----------  -------------  ----- 
1        2012-01-01  2012-01-04     1     
1        2012-01-05  2012-01-08     2     
1        2012-01-09  2012-01-12     1

2021-05-10