小编典典

连接两个层次查询以形成更大的层次

sql

我已经对此进行了研究,并且知道我不是第一个提出问题的人,但是我似乎无法解决这个问题。我创建了一个简单的示例,如果有人可以提供缺少的链接,我认为它将帮助我破解它!

我有一张表,其中包含按层次结构划分的大洲和国家。

我还有一张表格,其中包含按层次结构排列的城市和地标。该表包含一个区域ID列,以连接到区域表。

    create table areas
(
  id            NUMBER not null,
  name          VARCHAR2(200) not null,
  parent_id     NUMBER
);

-- Top Level
Insert into areas (id, name)
 Values (1, 'Europe');
Insert into areas (id, name)
 Values (2, 'Americas');
Insert into areas (id, name)
 Values (3, 'Asia ex Japan');
Insert into areas (id, name)
 Values (4, 'Japan');

 -- Jurisdictions
Insert into areas (id, name, parent_id)
 Values (5, 'UK', 1);
Insert into areas (id, name, parent_id)
 Values (7, 'France', 1);
Insert into areas (id, name, parent_id)
 Values (6, 'Germany', 1);
Insert into areas (id, name, parent_id)
 Values (8, 'Italy', 1);
Insert into areas (id, name, parent_id)
 Values (9, 'US', 2);
Insert into areas (id, name, parent_id)
 Values (10, 'Australia', 3);
Insert into areas (id, name, parent_id)
 Values (11, 'New Zealand', 3);

create table places
(
  id            NUMBER not null,
  name          VARCHAR2(200) not null,
  area_id       NUMBER,
  parent_id     NUMBER
);

Insert into places (id, name, area_id, parent_id)
 Values (1, 'London', 5, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (2, 'Bath', 5, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (3, 'Liverpool', 5, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (4, 'Paris', 7, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (5, 'New York', 9, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (6, 'Chicago', 9, NULL);
Insert into places (id, name, area_id, parent_id)
 Values (7, 'Kings Cross', 5, 1);
Insert into places (id, name, area_id, parent_id)
 Values (8, 'Tower of London', 5, 1);

我可以这样独立查询这些表:

 SELECT a.*, level FROM areas a
start with parent_id is null
connect by prior id = parent_id

SELECT p.*, level FROM places p
start with parent_id is null
connect by prior id = parent_id

有人可以告诉我最后一步,将它们分为四个级别的一个查询吗?我已经在Oracle上工作了多年,但是以某种方式却从未实现过!

如果在places表中没有按先验连接,则仅列出一个具有区域ID的城市,这会更容易吗?

谢谢


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2021-05-23

共1个答案

小编典典

是你需要的吗?

with src as (
  select 'A' type, a.id, a.name, a.parent_id, null area_id from areas a
  union all
  select 'P', -p.id id, p.name, -p.parent_id parent_id, area_id from places p)
select 
  src.*, level
from 
  src
start with 
  type = 'A' and parent_id is null
connect by 
  parent_id = prior id or 
  parent_id is null and area_id = prior id
2021-05-23