经典ASP从SQL2005获取SCOPE

admin

经典ASP从SQL2005获取SCOPE_IDENTITY（）值

sql

我无法弄清楚如何从SQL2005存储过程将SCOPE_IDENTITY（）返回到我的变量。

我的sSQL字符串：

sSQL = "EXEC [sp_NewClaim] " & Chr(34) & ClaimNumber & Chr(34) & ", " & Request.Cookies("UserID") & ", " & Request.Cookies("MasterID") & ", " & Chr(34) & strRestaurante & Chr(34) & ", " & Chr(34) &  Fecha & Chr(34) & ", " & Chr(34) & Hora & Chr(34) & ", " & Chr(34) & Request("Tiempo") & Chr(34) & ", " & Chr(34) & Request("Luz") & Chr(34) & ", " & Chr(34) & Request("Desc") & Chr(34) & ", " & Chr(34) & Request("incidente") & Chr(34) & ", " & Chr(34) & Request("codigos") & Chr(34) & ", False, 0; SELECT RecordNumber = SCOPE_IDENTITY()"

我的sSQL输出：

EXEC [sp_NewClaim] "W200811", 7, 8, "Otro -- WORK PLEASE", "11/19/2008", "01:19 PM", "Nublado", "Mala", "asdasd", "uyiuyui", "C-Junta", False, 0; SELECT RecordNumber = SCOPE_IDENTITY()

执行我的SQL命令：

Set rsData= Server.CreateObject("ADODB.Recordset")
rsData.Open sSQL, conDB, adOpenKeyset, adLockOptimistic

尝试输出SCOPE_IDENTITY（）会产生一个空变量（无输出）：

Response.Write("<br />Record Number: " & rsData("RecordNumber"))

存储过程正确运行。我的信息被毫无问题地存储到我的数据库中。RecordNumber是具有标识的列，并且存储过程已将@RecordNumber定义为输出：

USE [db_clcinsurance_com]
GO

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE PROCEDURE sp_NewClaim
 (
    @ClaimNumber nvarchar(50),
    @blah............
    .................
    @RecordNumber INT OUTPUT
    )
AS

BEGIN

    INSERT INTO Accidente (ClaimNumber,........., RecordNumber)

    VALUES (@ClaimNumber,....., @RecordNumber)

    SET @RecordNumber = SCOPE_IDENTITY();

END

阅读 208

2021-06-07

共1个答案

admin

对于您的存储过程，请执行以下操作：

CREATE PROCEDURE sp_NewClaim
 (
    @ClaimNumber nvarchar(50),
    @blah............
    .................
)
AS
BEGIN
    SET NOCOUNT ON;

    INSERT INTO Accidente (ClaimNumber,........., RecordNumber)
        VALUES (@ClaimNumber,....., @RecordNumber)

    SELECT SCOPE_IDENTITY()
END

然后以与检索其他任何查询结果相同的方式获取ID。

2021-06-07